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- Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 137 to 187 cm and weights of 37 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.31 cm, y = 81.36 kg, r= 0.351, P-value = 0.000, and y = - 103 +1.17x. Find the best predicted value of y (weight) given an adult male who is 171 cm tall. Use a 0.05 significance level. The best predicted value of y for an adult male who is 171 cm tall is (Round to two decimal places as needed.) kg.Studies have shown that people who suffer sudden cardiac arrest have a better chance of survival if a defibrillator shock is administered very soon after cardiac arrest. How is survival rate related to the time between when cardiac arrest occurs and when the defibrillator shock is delivered? = survival rate (percent) and x = mean call-to-shock time (minutes) for a cardiac rehabilitation center (in which cardiac arrests occurred while victims were hospitalized The accompanying data give y and so the call-to-shock time tended to be short) and for four communities of different sizes. Mean call-to-shock time, x 2 6. 7 9. 12 Survival rate, y 91 46 32 4Consider a function R(r, y) = /y. Assuming r and y are correlated, what is the standard deviation of R as a function of r, y, and their standard deviations? IHR = 1/y were an eficiency for a detector, with y representing the total number of events in which a particle passed through and ar the subset of events in which the detector activated, would the calculation above apply? Why or why not? Write down the equation for the binomial error on an efficiency measurement, explaining in
- The first of the two samples has 100 items with mean 15 and standard deviation 3. If the whole group has 250 items with mean 15-6 and standard deviation √13-44, find the standard deviation of the second group. Solution IHeights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 132 to 194 cm and weights of 38 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x 167.75 cm, y=81.58 kg, r0.318, P.value = 0.001, and y-109 1.14x. Find the best predicted value of y (weight) given an adult male who is 184 cm tal, Use a 0.05 significance level. The best predicted value of y for an adult male who is 184 cm tall is kg. (Round to two decimal places as needed.)A variable of two populations has a mean of 30 and a standard deviation of 24 for one of the populations and a mean of 30 and a standard deviation of 40 for the other population. Complete parts (a) through (c). a. For independent samples of size 9 and 4, respectively, find the mean and standard deviation of x1−x2. (Assume that the sampling is done with replacement or that the population is large enough.) The mean of x1−x2 is _________ (Type an integer or a decimal. Do not round.) The standard deviation of x1−x2 is _________ (Round to four decimal places as needed.) b. Must the variable under consideration be normally distributed on each of the two populations for you to answer part (a)? Choose the correct answer below. A. No, the variable must be approximately normally distributed on at least one of the two populations for the formulas for the mean and standard deviation of x1−x2to hold, as long as the sampling is done with replacement. B. No, the variable…
- We analyze a data set with Y = stopping distance of a car and X = speed of the car when the brakes were applied, %3D and after running the data in STATISTICA, we obtain the following results. Std.Err. of b Std.Err. of b* t(61) p-value b* N=63 Intercept Speed -20.2734 3.1366 -6.26038 20.67978 0.000000 0.000000 3.238368 0.935504 0.045238 0.151674 Sums of df Mean p-value Squares Squares 59540.15 Effect 59540.15 427.6534 0.000000 Regress. Residual 1 8492.74 61 139.23 Total 68032.89 Speed X StopDist Y Speed squared StopDist squared Speed StopDist 65853 Total 1195 2471 28719 164951 One of the observations is (X = 39, Y = 138). The value of the internal studentized residual is . (final answer to 2 decimal places e.g. 2.12) Hence, the point (39, 138) an outlier. (choose from is or is not)A variable of two populations has a mean of 55 and a standard deviation of 36 for one of the populations and a mean of 55 and a standard deviation of 10 for the other population. Complete parts (a) through (c). a. For independent samples of size 9 and 4, respectively, find the mean and standard deviation of x1−x2. (Assume that the sampling is done with replacement or that the population is large enough.) The mean of x1−x2 is _________ (Type an integer or a decimal. Do not round.) The standard deviation of x1−x2 is _________ (Round to four decimal places as needed.) b. Must the variable under consideration be normally distributed on each of the two populations for you to answer part (a)? Choose the correct answer below. A. No, the variable must be approximately normally distributed on at least one of the two populations for the formulas for the mean and standard deviation of x1−x2to hold, as long as the sampling is done with replacement. B. No, the variable…Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 139 to 190 cm and weights of 39 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.58 cm, y = 81.30 kg. r=0.101, P-value = 0.317, and y=-108 + 1.16x. Find the best predicted value of ŷ (weight) given an adult male who is 179 cm tall. Use a 0.10 significance level. The best predicted value of y for an adult male who is 179 cm tall is (Round to two decimal places as needed.) kg.
- For a life aged 35, you are given a force of interest, 6=0.10, and a force of mortality, a= 0.06. This life purchases a ten-year deferred whole life insurance with a benefit of one payable at the moment of death. Z is the present value at poliey issue of the benefit for this insurance. Determine the 90th percentile of Z .A population has a mean of μ = 60 and a standard deviation of σ = 12. For the same population, find the score (X value) that corresponds to each of the following z-scores. z = 0.50z = −0.25 z = 1.50z = −0.50 z = −2.50z = 1.25A random sample of 70 observations produced a mean off x =24.1 from a population with a normal distribution and a standard deviation σ=3.68.
