Suppose a 250. mL flask is filled with 1.2 mol of H,0, 1.8 mol of CO, and 2.0 mol of H,. The following reaction becomes possible: CO({) +H,0(2) = CO,(e) +H,(e) The equilibrium constant K for this reaction is 0.175 at the temperature of the flask. IS Calculate the equilibrium molarity of H,O. Round your answer to two decimal places. OM

Consider the equilibrium system described by the chemical reaction below. For this reaction, Kc = 2.4 x 103 at a particular temperature. If the equilibrium concentrations of H,0 and H, are 0.11 M and 0.019 M, respectively, determine the concentration of O, at equilibrium.. 2 2 H,O(g) = 2 H,(g) + 0,(g) 2 NEXT > If [x] represents the equilibrium concentration of O, set up the equilibrium expression for Kc to solve for the concentration. Do not combine or simplify terms.. 2' K. = = 2.4 x 103 5 RESET [О.11] [0.019] 2[0.11] 2[0.019] [0.11]? [0.019]? [x] [x]? [2x] [2x]?

Suppose a 250. mL flask is filled with 1.1 mol of CO, 0.80 mol of H,O and 0.60 mol of CO,. The following reaction becomes possible: CO(g) +H,0(g) - CO,(g)+H2(g) The equilibrium constant K for this reaction is 5.72 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. | M

At a certain temperature, the equilibrium constant K for the following reaction is 6.0 x 10: co(e) + H,0(g) -co,() + H,(g) Use this information to complete the following table. Suppose a 31. L reaction vessel is filled with 1.1 mol of co, and 1.1 mol of H2. What can you say about the composition of the mixture in the vessel at equilibrium? O There will be very little CO and H,0. O There will be very little Co, and H,. O Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. K = ] Co,(0)+H,(0) CO()+H,O(9) 1. What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. K = ] 3 CO0g)+3H,0(9) 3 CO,(0)+3H,(9) 1.

Suppose a 500. mL flask is filled with 1.8 mol of Cl,, 1.6 mol of CHCI, and 1.7 mol of HCl. The following reaction becomes possible: Cl,(g) +CHCI, (g) HCl(g)+CCl,(g) The equilibrium constant K for this reaction is 0.642 at the temperature of the flask. Calculate the equilibrium molarity of CHCI,. Round your answer to two decimal places.

The equilibrium constant, K., for the following reaction is 1.29×102 at 600 K. COCI,(e)=CO(g) + Cl,(g) Calculate the equilibrium concentrations of reactant and products when 0.270 moles of COCl2(g) are introduced into a 1.00 L vessel at 600 K. [COC,] = | M [CO] M [Cl,] M

O KINETICS AND EQUILIBRIUM 1/5 Calculating equilibrium composition from an equilibrium constant Suppose a 500. mL flask is filled with 1.1 mol of Cl,, 0.20 mol of HCl and 0.80 mol of CCl,. The following reaction becomes possible: Cl,(g) +CHCI, (g) = HCl(g)+CCl, (g) The equilibrium constant K for this reaction is 9.65 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places. | M II

Calculating equilibrium composition from an equilibrium... 0/5 Suppose 500. mL flask is filled with 1.9 mol of H, and o0.50 mol of C1,. The following reaction becomes possible: H, (g) + Cl,(g) – 2HC1(g) The equilibrium constant K for this reaction is 3.61 at the temperature of the flask. Calculate the equilibrium molarity of H,. Round your answer to two decimal places. OM

Suppose a 500. mL flask is filled with 0.80 mol of H, and 0.90 mol of HI. The following reaction becomes possible: H, (g) +1,(g) – 2HI(g) The equilibrium constant K for this reaction is 3.50 at the temperature of the flask. Calculate the equilibrium molarity of I,. Round your answer to two decimal places. ?

At a certain temperature, the equilibrium constant K for the following reaction is 1.0: H,(g) + I,(g) = 2 HI(g) Use this information to complete the following table. Suppose a 38. L reaction vessel is filled with 1.0 mol of H, and 1.0 mol of I,. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and I. There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. %3D 2 HI(g) H,(0)+I,(9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. K =] 2 H,(0)+21,(0) 4 HI(g) 1. Fynlanation Check