sum1 = 0; for (k=1; k<=n; k*=2) for (j=1; j<=n; j++) sum1++; sum2 = 0; for (k=1; k<=n; k*=2) for (j=1; j<=k; j++) sum2++; [First is E"n = O(n log n). Second is - 2* = ©(n).] log n-1 k=1 k=0

In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation).…

write a STRUCTURAL verilog code to find 1's complement & 2's complement for a variable ( compile verilog online is prefered to use !)

Point out the difference between   int pthread_mutex_lock ( pthread_mutex_t *mutex_lock);   and      int pthread_mutex_trylock (    pthread_mutex_t *mutex_lock);

Print the series 1, 11, .......91 in the output using loops in C language.

Convert the infix expression to postfix: a+b/c+d