Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2 SO2(9)+O3(9) → 2 SO 3(g) Use this chemical equation to answer the questions in the table below. Suppose 65.0 mmol of SO, and None. 32.5 mmol of O, are added to an Some, but less than 65.0 mmol. O 65.0 mmol. empty flask. How much SO,3 will be in the flask at equilibrium? 3. More than 65.0 mmol. O None. Suppose 175. mmol of SO, are Some, but less than 175. mmol. added to an empty flask. How much SO, will be in the flask at 175. mmol. equilibrium? O More than 175. mmol.
Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2 SO2(9)+O3(9) → 2 SO 3(g) Use this chemical equation to answer the questions in the table below. Suppose 65.0 mmol of SO, and None. 32.5 mmol of O, are added to an Some, but less than 65.0 mmol. O 65.0 mmol. empty flask. How much SO,3 will be in the flask at equilibrium? 3. More than 65.0 mmol. O None. Suppose 175. mmol of SO, are Some, but less than 175. mmol. added to an empty flask. How much SO, will be in the flask at 175. mmol. equilibrium? O More than 175. mmol.
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter3: Mass Relations In Chemistry; Stoichiometry
Section: Chapter Questions
Problem 55QAP: One way to remove nitrogen oxide (NO) from smoke-stack emissions is to react it with ammonia....
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Transcribed Image Text:Sulfur dioxide and oxygen react to form sulfur trioxide, like this:
2 SO 2(g)+O2(9) –
2 SO 3(9)
Use this chemical equation to answer the questions in the table below.
Suppose 65.0 mmol of SO, and
None.
32.5 mmol of O, are added to an
Some, but less than 65.0 mmol.
empty flask. How much SO,3 will be
65.0 mmol.
in the flask at equilibrium?
More than 65.0 mmol.
Suppose 175. mmol of SO, are
O None.
added to
empty flask. How much
Some, but less than 175. mmol.
SO, will be in the flask at
O 175. mmol.
equilibrium?
O More than 175. mmol.
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