Sulfur-38 Original amount: 5.0 g Amount left: c Total time: 8.61 h Half-life: 2.87 h Number of half-lives:

em1.png Part 3: Q9 Average absorbance Flask 8 Flask 9 Flask 10 1:1 Ratio so, Flask 11 Part 3: Q Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q10 Flask 8 Flask 9 Flask 10 Flask 11 Part 3 0.146 0.166 [Fe] -0.002mol/L 0.215 0.294 [FESCN³mol/L) 4.59% 10 5.18*10* 6.64*10* 9.08*10* [FXmol/L) 5.00 *10* 5.00*10* Y=3362x-0.0083 R² = 0.9993 5.00*10* 5.00*10* (Amounts of flask 8 (9 - 11's values are in the spreadsheet) 71% volume 5.00mL Molarity of Fe(NO3))3 = 0.2M Volume of Fe(NO3))3 = 5.00mL Moles of Fe³= Molarity x volume(L) Moles of Fe¹ = 0.2M X 0.005L = 1x10-³mole x [SCN][mol/ 4x10 5×10-4 7x10 1×10 1 Concentration of Fe³ = mole of Fe³ Volume mole of Fe³1x10³ mole G.O05L 8, Average absorbance for solution 8 (same for 9 - 11) Average absorbance for flask 8 = sum of all absorbances / number of readings (0.145 +0.147 +0.148) 3 Using equation of calibration curve's line(slope) of best fit, the average absorbances of the unknown concentrations to determine [FeSCN-Jat equilibrium in solution 8:…

Sample #1 has an absorbance of 0.300. Sample #2 is the same substance and has an absorbance of 0.600 using the same equipment. What is the relative concentration of the second sample? Select one: a. The concentration of sample #2 is the square root of that of #1. b. The concentration of sample #2 is that of sample #1 squared. c. The concentration of sample #2 is half that of sample #1. d. The concentration of sample #2 is twice that of sample #1.

. Describe your results. What is the shape of the graph of absorbance vs concentration? What does this tell us about crystal violet solutions?