Given that for a flow process the steady flow equation is q- w = (u2 – u1) +(P2v2 – Pv1)++ g(z2- zı)2where: q is heat per kg to or from the system (J/kg)w is work per kg to or from the system (J/kg)u is the internal energy per kg (J/kg)Pis the pressure (N/m²)v is the specific volume or volume per kg (m³/kg)C is the velocity of flow (m/s)g is gravity (m/s²)z is height above the datum (m)subscript 1 and 2 denotes inlet and outlet, respectively.Determine the value of work, w in J/kg, ifq = 10*10³ J/kgu2 = 0.5*10° J/kg, ui-2.0*10° J/kgP1 = 6.2*10$ N/m?Vi = 0.37m³/kg, v2 = 1.2m³/kgCi= 300 m/s, C2 = 100 m/sP2 = 3*10$ N/m?g = 9.81 m/s²zi = 2m, z2 = 2m

As all the parameters properly explained in question then the steady flow equation is q-w =…

subscript 1 and 2 denotes inlet and outlet, respectively. Determine the value of work, w in J/kg, if q = 10*10³ J/kg u2 = 0.5*10° J/kg , uj=2.0*10° J/kg P = 6.2*10° N/m² P2 = 3*10° N/m Vi = 0.37m³/kg, v2 = 1.2m³/kg Ci= 300 m/s, C2 = 100 m/s g = 9.81 m/s² 2m Zi = 2m, z2 =

subscript 1 and 2 denotes inlet and outlet, respectively. Determine the value of work, w in J/kg, if q = 1010³ J/kg u2 = 0.510° J/kg , uj=2.010° J/kg P = 6.210° N/m² P2 = 3*10° N/m Vi = 0.37m³/kg, v2 = 1.2m³/kg Ci= 300 m/s, C2 = 100 m/s g = 9.81 m/s² 2m Zi = 2m, z2 =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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