Explain very briefly your answer.Give a practical example of such a system. A closed thermodynamic system consists of a fixed amount of substance (i.e. mass)in which no substance can flow across the boundary, but energy can. For a closedthemodynamic system we cannot add energy to the system, via substance (E ) (1.e. matterwhich contains energy is not allowed across the boundary)Across the BoundariesE° = NoQ == YesWmass NOCLOSED= YesSY STEMm = constant| energy YESFigure 1.1.If the substance inside the thermodynamic system shown in figure 1.1. (i.e. pistoncylinder device) is air, is the system aFixed closed systemMoveable closed systemA.В.

In thermodynamic, system is that portion of space where our interest lies, where we want to…

Answered: mass NO CLOSED | SY STEM m = constant…

Engineering

Mechanical Engineering

mass NO CLOSED | SY STEM m = constant energy YES

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

M: Constarm h=chang Q2. Heat cannot be zero in closed system (True/False). ( F cee Q1. Work cannot be zero in closed system (True/False) Q3. First law of thermodynamics is not based on the law of conservation of energy (True/False), Q4. The change in the total energy of the closed system is -Q5. The sum of the'energiesCarried by the mass in open system is.Mashalase Emi =Eme Q-w=AH fluichProleabie.haT ehange with Time Q6. The general form of first law of thermodynamics for open system.. Q7. Un steady state flow process is defined as. internal+ Q8. Enthalpy is defined sum of kinetic and flow energy (True False), 09. Cyclic process is defined as.wha.h.ystem start from initial state trour, L diffrent Processes and .e.k... Q10. Internal energy is considered in open system (True/False)İ
Which of the following is intensive property heat: work, internal energy, specific heat, heat capacity, pressure
The 1st law of thermodynamics is ΔU = Q –W. Use this statement of the 1st law to show (mathematically) its equivalent statement: “Total energy of the universe is constant”. Here, the universe can be defined as: system + surroundings (everything but the system –everything outside the system). (Hint: this can be shown by two ways-you may either treat system and surroundings as two systems next to each other, or you may treat system + surroundings (universe) as one system.)
Q1. (Reading: Çengel and Boles, Thermodynamics: An Engineering Approach, 8th Ed., Pages 307-311) The amount of energy waste by a refrigerator increases by a number of malpractices. For example; opening the refrigerator door frequently will increase energy waste as the warmer air outside replaces the cool air inside. It is also not recommended to place the hot foods into the refrigerator before cooling them to the room temperature. Imagine a typical household refrigerator with an internal temperature of 4 °C. The refrigerator has a coefficient of performance of 1.4. The internal dimensions of this refrigerator are 186 cm (height) x 84 cm (width) x 75 cm (depth). The half of the refrigerator volume is used for storing food items. The air filling the other half of the refrigator volume contains 0.004 kg moisture/kg air on average. While the moisture content of the air in the kitchen is 0.01 kg/kg air, the temperature and pressure in the kitchen are 23°C and 97 kPa, respectively. Assuming…
A gas contained within a piston-cylinder assembly undergoes three processes in series: Process 1-2: Constant volume from p₁ = 1 bar, V₁ = 4 m³ to state 2, where p2 = 2 bar. Process 2-3: Compression to V3 = 2 m³, during which the pressure-volume relationship is pV = constant. Process 3-4: Constant pressure to state 4, where V4 = 1 m³. Sketch the processes in series p-V coordinates and evaluate the work for each process, in kJ. Hint: Draw all the processes neatly on P-V diagram. Denote the states 1-4. Do not forget to add arrows.
Thermodynamics systems have been playing important roles in our life.Briefly explain one of the systems and the concepts of the system(type, properties, etc.)
A century-old platter falls vertically downward. Upon breaking, its fragments fly off parallel to the ground with velocity 1= 2.2 m/s and V2 = 15 m/s. Find mass ml and mass m2 in kg Vi 25.0° m2 45.0° m3 = 1.30 kg 3.07 m/s Select one *a. ml = 13551; m2 = 0.7180 Ob. ml = 1.3551; m2 = 1.1966 O. ml= 1.1966; m2 = 1.3651 Od ml =0.68; m2 = 0.96
Drag and Drop the correct answers in the blanks. A mass mis hanging from the end of a vertical spring that has a spring constant k. The equilibrium position of the mass, yo, is The total potential energy of the mass when it is displaced by s from the equilibrium position is given by Y. is zero + U(s) = ks + positive * negative 1 1 ks+ 21 + U(s) ks² + mgyo %3D U(s) mgyo
A cryogenic substance is found to have a specific heat capacity (at constant volume) c_v that varies with temperature according to c_v = AT^2, where A is an empirically derived constant with units J/(K^3 kg). If 220 J of energy must be transferred thermally (at constant volume) to an 8,750 mg sample of this substance to raise the temperature of the sample from 1.0 K to 6.6 K, what is the value of A? Your Answer: Answer units
2. Which one of the following is the extensive property of a thermodynamic system? (a) Volume (b) Pressure (c) Temperature (d) Density
A fluid is contained in a cylinder by a spring-loaded, frictionless piston so that the pressure in the fluid is linear function of the volume (p = a + bV). The internal energy of the fluid is given by the following equation U = 34 + 3.15 pVwhere U is in kJ, p in kPa and V in cubic metre. If the fluid changes from an initial state of 173 kPa, 0.03 m3to a final state of 400 kPa, 0.06 m3, with no work other than that done on the piston, find the direction and magnitude of the work and heat transfer.
Match the laws accordingly. 1.1st law of thermodynamics 2.2nd law of thermodynamics (foward engine) 3.Joules law 4.2nd law of thermodynamics (reverse engine) 5.3rd law of thermodynamics 6.second law of thermodynamics (Carnot) A. The internal energy of a perfect gas is a function of the absolute temperature only B. No Heat Engine can be more efficient than a Reversible Heat Engine operating between the same temperature limits C. A pure crystalline substance at absolute zero temperature is in perfect order, and its entropy is zero D. When a system undergoes a complete cycle, the net Heat supplied plus the net Work input is zero. E. It is impossible for a heat engine to produce a net work output in a complete cycle if it exchanges heat only with a single energy reservoir. F. It is impossible to construct a device that operating in a cycle will produce no effect other than the transfer of heat from a cooler to a hotter body.