Student 1: We know the Sun rises in the east and moves through the southern part of the sky and then sets in the west. Eight hours after sunrise it makes sense that the Sun will have moved from being on the eastern horizon near the constellation Cancer to being located high in the southwestern sky near the constellation Aries. Student 2: You're forgetting that some stars and constellations also move from the east through the southern sky and to the west just like the Sun. So, the Sun will still be near Cancer 8 hours later. So in Figure 5 is drawn incorrectly. It should show that the constellations have all moved like the Sun, so Cancer would also be located high in the southwestern sky, with the Sun, eight hours later. Do you agree or disagree with either or both of the students? Explain your reasoning. Check your answers with another group. 12) In question 11, we found that Figure 5 was drawn incorrectly. Redraw Figure 5 on the figure below by sketching the approximate location of any constellation from Figure 5 that would still be visible. South East West

An object is placed 12 cm in front of a convex mirror of radius 40 cm. Find the position and magnification of the image. State whether the image is real or virtual, and draw a light ray diagram to show the image.

2. 11.3 cm,-0.4 cm 2. A concave mirror has f = 10.5 cm. An object that is 5.2 cm tall is placed 1.5 m away from the mirror. Sketch the ray diagram. Find image height and distance. Describe image.

Shown in the figure below is a system containing two lenses and an object. The focal lengths of the two lenses are f = 15 cm %3D and f, = -7.5 cm. The two lengths indicated in the figure are L, = 22.5 cm and L2 = 12 cm. f1 f2 L2 Determine all the following about the image from the first lens only: Object distance for the first lens, do1. cm Image distance for the first lens, di1. cm Magnification of the first lens, m1. The second lens uses the image from the first lens as its object. Determine all the following about the image from the second lens: Object distance for the second lens, do1. cm Image distance for the second lens, di1. cm Magnification of the second lens, m1. Determine the magnification of the whole system, mtot. Select the correct attributes of the final image of the system: O virtual O real O shrunk O enlarged right side up O upside down

Solved the mobile problem. I would also like to see your work written (or typed) on paper as much as possible also like a detail.  I attach an image of the question. Please write detail to solve the solution.

I know it’s not real and virtual. I don’t think it’s real so I’m thinking it’s just virtual but I’m not sure.

The image of the coin in the figure is magnified by a factor of M = 4.7 times, and is a distance d = 9.4 cm from the lens. What is the focal length (in cm) of the lens? cm i

A certain slide projector has a 110 mm focal length lens.   A. How far away is the screen (in m), if a slide is placed 115 mm from the lens and produces a sharp image?   B. If the slide is 15.0 by 30.0 mm, what are the dimensions of the image? __ cm by __ cm.

Chapter 34, Problem 034 SN When an object is placed a distance p in front of a spherical refracting surface with radius of curvature r, the image distance is i. If the index of refraction of the surrounding material Is n1, what is the index of refraction of the refracting material? State your answer in terms of the given variables. n2 = 2 Edit

A small object is placed to the left of a convex lens and on its optical axis. The object is 46 cm from the lens, which has a focal length of 15 cm.Determine the location of the image formed by the lens. (Enter your answer in cm from the lens.) 1. cm from the lens 2. Describe the image.