The vertical distance between eye level and the ground for a certain swimmer, who is standing upright, is 1.55 m. If the swimmer is standing 2.00 m from the edge of a 2.50-m-deep swimming pool, how far from the base of the pool will the swimmer be able to see a coin that is at the bottom of the pool? The swimmer is represented by the upward directed arrow in the diagram, and the distance between the base of the pool and the coin is “d”. The index of refraction of water is 1.33. a. 1.55 m b. 0.950 m c. 1.85 m d. 2.15 m e. 1.25 m

An underwater scuba diver sees the Sun at an apparent angle of 31.0° from the vertical. What is actual direction of the Sun? ° (above the horizon)

デジタル形式で段階的に解決 ありがとう!! SOLVE STEP BY STEP IN DIGITAL FORMAT While standing on top of a 50.0 m tall building, you discover a friend standing on the street corner. Using a protractor and a plumb line, he finds that the angle between the horizontal and the direction toward the point on the sidewalk where his friend is standing is 25.0°. His eyes are located 1.75 m above the top of the building. How far from the building level is his friend?

Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 7.5 cm (left lens) and 35 cm (right lens) are separated by a distance 25 cm.     If a 2.9 cm tall object is placed as indicated in part (a), and the image formed is 0.74 cm tall, what is the magnification of the first lens?  M1 =  b. Using the information from part (a), calculate the image distance, in centimeters, from the first lens.  di1 =