Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Solutions
Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to a…
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Given that the vapor pressure of water is 17.54 torr at 20 °C, calculate the vapor-pressure lowering of aqueous solutions that are 2.40 m in sucrose, C,,H,01 , and sodium chloride. STRATEGY 1. Determine the colligative molality of each solution. 2. Convert each colligative molality to a mole fraction. 3. Apply Raoult's law. Step 1: Sucrose is a nonelectrolyte, whereas NaCl has 2 ions per formula unit. sucrose: 2.40 m NaCl: 2(2.40 m) = 4.80 m Step 2: If you assume 1 kg of solvent, then the number of moles of solute is equal to the molality. Convert 1 kg of water to moles. 1 kg H,0 = H,O Calculate the mole fraction, x, of a solution with 2.40 mol of sucrose and 1 kg of water. Xsucrose = Calculate the mole fraction, x, of a solution with 4.80 mol of NaCl and 1 kg of water. Question Source: MRG-General Chemistry MacBook Air 000 D00 F4 F5 F7 F8 F9 F10 & * 4 5 6 7 8 9
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Transcribed Image Text:Given that the vapor pressure of water is 17.54 torr at 20 °C, calculate the vapor-pressure lowering of aqueous solutions that are 2.40 m in sucrose, C,,H,01 , and sodium chloride. STRATEGY 1. Determine the colligative molality of each solution. 2. Convert each colligative molality to a mole fraction. 3. Apply Raoult's law. Step 1: Sucrose is a nonelectrolyte, whereas NaCl has 2 ions per formula unit. sucrose: 2.40 m NaCl: 2(2.40 m) = 4.80 m Step 2: If you assume 1 kg of solvent, then the number of moles of solute is equal to the molality. Convert 1 kg of water to moles. 1 kg H,0 = H,O Calculate the mole fraction, x, of a solution with 2.40 mol of sucrose and 1 kg of water. Xsucrose = Calculate the mole fraction, x, of a solution with 4.80 mol of NaCl and 1 kg of water. Question Source: MRG-General Chemistry MacBook Air 000 D00 F4 F5 F7 F8 F9 F10 & * 4 5 6 7 8 9
Expert Solution
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Step 1

a) Moles of 1 kg water

1 kg = 1000 g

Moles = MassMolar massMoles of water =1000 g18 g/mol =55.56 mol

Moles of water = 55.56 mol

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