Step 2: If you assume 1 kg of solvent, then the number of moles of solute is equal to the molality. Convert 1 kg of water to moles. 1 kg H,O = mol H,O Calculate the mole fraction, x, of a solution with 2.40 mol of sucrose and 1 kg of water.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given that the vapor pressure of water is 17.54 torr at 20 °C, calculate the vapor-pressure lowering of aqueous solutions
that are 2.40 m in sucrose, C,,H,01 , and sodium chloride.
STRATEGY
1. Determine the colligative molality of each solution.
2. Convert each colligative molality to a mole fraction.
3. Apply Raoult's law.
Step 1: Sucrose is a nonelectrolyte, whereas NaCl has 2 ions per formula unit.
sucrose: 2.40 m
NaCl: 2(2.40 m) = 4.80 m
Step 2: If you assume 1 kg of solvent, then the number of moles of solute is equal to the molality. Convert 1 kg of water
to moles.
1 kg H,0 =
H,O
Calculate the mole fraction, x, of a solution with 2.40 mol of sucrose and 1 kg of water.
Xsucrose =
Calculate the mole fraction, x, of a solution with 4.80 mol of NaCl and 1 kg of water.
Question Source: MRG-General Chemistry
MacBook Air
000
D00 F4
F5
F7
F8
F9
F10
&
*
4
5
6
7
8
9
Transcribed Image Text:Given that the vapor pressure of water is 17.54 torr at 20 °C, calculate the vapor-pressure lowering of aqueous solutions that are 2.40 m in sucrose, C,,H,01 , and sodium chloride. STRATEGY 1. Determine the colligative molality of each solution. 2. Convert each colligative molality to a mole fraction. 3. Apply Raoult's law. Step 1: Sucrose is a nonelectrolyte, whereas NaCl has 2 ions per formula unit. sucrose: 2.40 m NaCl: 2(2.40 m) = 4.80 m Step 2: If you assume 1 kg of solvent, then the number of moles of solute is equal to the molality. Convert 1 kg of water to moles. 1 kg H,0 = H,O Calculate the mole fraction, x, of a solution with 2.40 mol of sucrose and 1 kg of water. Xsucrose = Calculate the mole fraction, x, of a solution with 4.80 mol of NaCl and 1 kg of water. Question Source: MRG-General Chemistry MacBook Air 000 D00 F4 F5 F7 F8 F9 F10 & * 4 5 6 7 8 9
Expert Solution
Step 1

a) Moles of 1 kg water

1 kg = 1000 g

Moles = MassMolar massMoles of water =1000 g18 g/mol =55.56 mol

Moles of water = 55.56 mol

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