Determine the molarity and mole fraction of a 1.03 m solution of acetone (CH3COCH3) dissolved in ethanol (C₂H5OH). (Density of acetone = 0.788 g/cm³; density of ethanol = 0.789 g/cm³.) Assume that the final volume equals the sum of the volumes of acetone and ethanol. mol/L molarity mole fraction

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Determine the molarity and mole fraction of a 1.03 m solution of acetone (CH3COCH3) dissolved in ethanol (C₂H5OH). (Density of acetone = 0.788 g/cm³; density of ethanol = 0.789 g/cm³.) Assume that the final
volume equals the sum of the volumes of acetone and ethanol.
molarity
mol/L
mole fraction
Transcribed Image Text:Determine the molarity and mole fraction of a 1.03 m solution of acetone (CH3COCH3) dissolved in ethanol (C₂H5OH). (Density of acetone = 0.788 g/cm³; density of ethanol = 0.789 g/cm³.) Assume that the final volume equals the sum of the volumes of acetone and ethanol. molarity mol/L mole fraction
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Step 1: Determine the Molarity and mole fraction of acetone solution from the given data:

Given,

the molality of the acetone solution = 1.03 m

density of acetone = 0.788 g/cm3

density of ethanol = 0.789 g/cm3

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