Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- a) The following table provides the concentration of compound ‘A’ in a hydration reaction. Determine the reaction order, rate constant and rate law for this reaction. Show the equations and graphs used to determine the answer with a clear justification. Time (min) Concentration of A (M) 67 90 161 70 241 59 381 40 479 32 545 27 604 24 b) Calculate the activation energy for the isomerization of reactant X to product Y using the following data for the variation of rate constant (k) with temperature. T (oC) 477 523 577 623 k 0.00018 0.0027 0.03 0.26arrow_forwardConsider the reaction data. A⟶productsA⟶products ? (?)T (K) ? (?−1)k (s−1) 275275 0.3800.380 675675 0.7470.747 a)What two points should be plotted to graphically determine the activation energy of this reaction? To avoid rounding errors, use at least three significant figures in all value x1=? x2=? y1=? y2=? b)Determine the rise, run, and slope of the line formed by these points. c)What is the activation energy of this reaction?arrow_forward2ClO2+2OH- —> ClO-3+ClO-2+H2O R=k[ClO2]2[OH-] What is the rate constant for the reaction given the rate law and data?arrow_forward
- For the reaction of NO with Br, the following data was obtained. Use the data below to determine the rate law expression for this reaction. In the rate law expression, include the numeric value of k (with units). Experiment # Initial [NO] (M) | Initial [Br2] (M) Initial Rate (M s) 0.0100 0.0200 0.0240 2 0.0400 0.0200 0.384 0.0100 0.0500 0.0600arrow_forward23. The following data were measured for the reaction BF3(g) + NH3(g) ---> F3BNH3(g) Experiment [BF3] (M) [NH3] (M) initial rate (M/s) 1 0.250 0.250 0.2130 2 0.250 0.125 0.1065 3 0.200 0.100 0.0682 4 0.350 0.100 0.1193 5 0.175 0.100 0.0596 What is the overall order of the reaction? Group of answer choices A. 3 B. 2 C. 1 D. 0arrow_forwardDetermine the rate law for the reaction A + B - C+D given the following experiment data. Trial [A]o 1 0.25 0.75 0.50 0.75 4.arrow_forward
- estion 3 of 3 Time and concentration data were collected for the reaction 0.52 A → products 0.48 0.44- t (s) [A] (M) 0. 0.52 0.40- 20 0.43 0.36- 40 0.35 0.32- 60 0.29 0.28 - 80 0.23 100 0.19 0.24 0.20. The blue curve is the plot of the data. The straight orange line is tangent to the blue curve at t = 40 s. 0.16. 0 10 20 30 40 50 60 70 80 90 t (s) Approximate the instantaneous rate of this reaction at time t = 40 s. instantaneous rate: M/s [A] (M)arrow_forwardTime and concentration data were collected for the reaction 0.52 A -> products 0.48 0.44 t(s) [A] (M) 0 0.52 0.40- 0.36 20 20 0.43 0.32 40 40 0.35 0.28 60 60 0.29 0.24 88 80 0.23 0.20. 0.16. 100 0.19 The blue curve is the plot of the data. The straight orange line is tangent to the blue curve at t = 40 s. Approximate the instantaneous rate of this reaction at time t = 40 s. instantaneous rate: M/s 0 10 20 30 40 50 60 70 80 90 100 t(s)arrow_forwardThe data below show the concentration of cyclobutane (C4H8) versus time for the following reaction: C4H8→2C2H4 Time (s) [C4H8] (M) 0 1.000 10 0.894 20 0.799 30 0.714 40 0.638 50 0.571 60 0.510 70 0.456 80 0.408 90 0.364 100 0.326 What is the rate of reaction when [C4H8]= 0.26 M ? Express your answer using two significant figures. Please show how to do this question and find the rate law without graphing it. Thank you.arrow_forward
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