**Exercise: Confidence Interval Estimation** A random sample of 11 items is drawn from a population whose standard deviation is unknown. The sample mean is \( \bar{x} = 810 \) and the sample standard deviation is \( s = 20 \). Use Appendix D to find the values of Student’s t. **(a)** Construct an interval estimate of \( \mu \) with 98% confidence. *(Round your answers to 3 decimal places.)* The 98% confidence interval is from _______ to _______. **(b)** Construct an interval estimate of \( \mu \) with 98% confidence, assuming that \( s = 40 \). *(Round your answers to 3 decimal places.)* The 98% confidence interval is from _______ to _______. **(c)** Construct an interval estimate of \( \mu \) with 98% confidence, assuming that \( s = 80 \). *(Round your answers to 3 decimal places.)* The 98% confidence interval is from _______ to _______. **(d)** Describe how the confidence interval changes as \( s \) increases. - The interval stays the same as \( s \) increases. - The interval gets wider as \( s \) increases. (Correct) *Note: Please refer to the table in Appendix D for the appropriate t values for constructing these confidence intervals.*

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**Exercise: Confidence Interval Estimation**

A random sample of 11 items is drawn from a population whose standard deviation is unknown. The sample mean is \( \bar{x} = 810 \) and the sample standard deviation is \( s = 20 \). Use Appendix D to find the values of Student’s t.

**(a)** Construct an interval estimate of \( \mu \) with 98% confidence. *(Round your answers to 3 decimal places.)*

The 98% confidence interval is from _______ to _______.

**(b)** Construct an interval estimate of \( \mu \) with 98% confidence, assuming that \( s = 40 \). *(Round your answers to 3 decimal places.)*

The 98% confidence interval is from _______ to _______.

**(c)** Construct an interval estimate of \( \mu \) with 98% confidence, assuming that \( s = 80 \). *(Round your answers to 3 decimal places.)*

The 98% confidence interval is from _______ to _______.

**(d)** Describe how the confidence interval changes as \( s \) increases.

- The interval stays the same as \( s \) increases.
- The interval gets wider as \( s \) increases. (Correct)

*Note: Please refer to the table in Appendix D for the appropriate t values for constructing these confidence intervals.*
Transcribed Image Text:**Exercise: Confidence Interval Estimation** A random sample of 11 items is drawn from a population whose standard deviation is unknown. The sample mean is \( \bar{x} = 810 \) and the sample standard deviation is \( s = 20 \). Use Appendix D to find the values of Student’s t. **(a)** Construct an interval estimate of \( \mu \) with 98% confidence. *(Round your answers to 3 decimal places.)* The 98% confidence interval is from _______ to _______. **(b)** Construct an interval estimate of \( \mu \) with 98% confidence, assuming that \( s = 40 \). *(Round your answers to 3 decimal places.)* The 98% confidence interval is from _______ to _______. **(c)** Construct an interval estimate of \( \mu \) with 98% confidence, assuming that \( s = 80 \). *(Round your answers to 3 decimal places.)* The 98% confidence interval is from _______ to _______. **(d)** Describe how the confidence interval changes as \( s \) increases. - The interval stays the same as \( s \) increases. - The interval gets wider as \( s \) increases. (Correct) *Note: Please refer to the table in Appendix D for the appropriate t values for constructing these confidence intervals.*
Expert Solution
Step 1

From the given information,

Sample size n =11

sample mean, x̅=810

sample standard deviation, s=20

Confidence level = 98%

Degrees of freedom: 24(=25-1).

Using Excel function, “=T.INV.2T (0.02,10)”, the critical value for two-tailed test at 98% confidence level is 2.7638.

The standard error is:

SE=sn=2011 =6.0302

Margin of error:

E=t(/2)SE  =2.7638×6.0302  =16.666

Confidence interval:

CI=±E  =810±16.666  =(793.334,826.666).

The 98% confidence interval is from 793.334 to 826.666.

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