MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- review(25): which of the following is not a true statement about Central Limt Theorem. for sample means? (a) If the sample size is large, it does'nt matter what shape the distribution of the population it was drawn from the normal distribution can still be used to perform to perform statistical inference. (b) If conditions are met, the mean of the sampling disrribition is equal to the mean of the population mean (c) The Central Limit Theorem helps us find probablities for sample means when those means are based on a random sample from the population. (d) all of these statements are true about Central Limit Theorem for sample meansarrow_forwardA random sample X1,X2,...,Xn is drawn from the normal distribution. i. Suppose μ is a known parameter. Find the maximum likelihood estimator for σ. ii. Find the bias and variance of the obtained estimatorarrow_forwardA simple random sample of size n = 37 is obtained from a population that is skewed left with µ = 31 and o=4. Does the population need to be normally distributed for the sampling distribution of x to be approximately normally distributed? Why? What is the sampling distribution of x? Does the population need to be normally distributed for the sampling distribution of x to be approximately normally distributed? Why? A. Yes. The central limit theorem states that the sampling variability of nonnormal populations will increase as the sample size increases. B. No. The central limit theorem states that only if the shape of the underlying population is normal or uniform does the sampling distribution of x become approximately normal as the sample size, n, increases. C. No. The central limit theorem states that regardless of the shape of the underlying population, the sampling distribution of x becomes approximately normal as the sample size, n, increases. D. Yes. The central limit theorem…arrow_forward
- Consider random samples of size 258 drawn from population A with proportion 0.17 and random samples of size 310 drawn from population B with proportion 0.27. (a) Find the standard error of the distribution of differences in sample proportions, P - PB- Round your answer for the standard error to three decimal places. standard error = (b) Are the sample sizes large enough for the Central Limit Theorem to apply? OYes O Noarrow_forwardtion list estion 11 estion 12 estion 13 estion 14 estion 15 estion 16 estion 17 crunch A simple random sample of size n = 53 is obtained from a population that is skewed left with μ=77 and o=4. Does the population need to be normally distributed for the sampling distribution of x to be approximately normally distributed? Why? What is the sampling distribution of x? the sample size increases. OB. Yes. The central limit theorem states that only for underlying populations that are normal is the shape of the sampling distribution of x normal, regardless of the sample size, n. OC. No. The central limit theorem states that only if the shape of the underlying population is normal or uniform does the sampling distribution of x become approximately normal as the sample size, n, increases. OD. No. The central limit theorem states that regardless of the shape of the underlying population, the sampling distribution of x becomes approximately normal as the sample size, n, increases. What is the…arrow_forward4. The pmf of a geometric distribution with parameter p is given by S p(1 – p)" n= 0, 1, 2, ... otherwise. Pn = Assume p> 0. Show that the variance is (1 – p)/p². Hint: Σ Eng" (1 – q)² n=0 for |g| < 1.arrow_forward
- G A simple random sample of size n=36 is obtained from a population that is skewed left with p=86 and o=2. Does the population need to be normally distributed for the sampling distribution of x to be approximately normally distributed? Why? What is the sampling distribution of x? Save Does the population need to be normally distributed for the sampling distribution of x to be approximately normally distributed? Why? A. No. The central limit theorem states that regardless of the shape of the underlying population, the sampling distribution of x becomes approximately normal as the sample size, n, increases. B. No. The central limit theorem states that only if the shape of the underlying population is normal or uniform does the sampling distribution of x become approximately normal as the sample size, n, increases. O C. Yes. The central limit theorem states that only for underlying populations that are normal is the shape of the sampling distribution of x normal, regardless of the sample…arrow_forwardQuestion 14 The Central Limit Theorem states that the sampling distribution of a sample mean, y, is approximately normal for O a. random samples taken from populations not known to be Normal if the sample size is large enough O b. The Central Limit Theorem states that the sampling distribution of the sample mean can never be approximated by a Normal Model O c. only random samples taken from populations that follow a Normal Model O d. small, biased samples taken from skewed populations A Moving to another question will save this response. etv 20 F9 임□ F3 F5 esc F2 F4 F1 # $ & * @ 5 8. 2 3 Q W E R tab A S D F H caps lockarrow_forwardQ.4-52arrow_forward
- (b) Compute an 88.9% Chebyshev interval around the population mean. Recall that Chebyshev's Theorem states that for any set of data and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least 1 - Therefore, for data with mean u and standard deviation a, at least 1 - of data must fall between u- ko and + ko. When k- 3, we have the following. 1- 1 or 88.9% Therefore, for any set of data, at least 88.9% of the data must fall between - 3a and or, in other words, within standard deviations of the mean.arrow_forwardA random sample of size 10 yielded roughly "mound-shaped" data with a sample mean of 63.5 and a sample variance of 60.8. Let (L, OU) be the interval estimate that contains the population mean with 95% probability. Find the width of the interval. That is, find 0 – 0₁. 4.52 5.49 5.58 5.70 9.04 10.99 11.16 11.40 none of the other answers give the correct widtharrow_forward
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