State whether the standardized test statistic t indicates that you should reject the null hypothesis. Explain.        T0=2.057   ​(a)t=2.092 ​(b)t=0 ​(c)t=2.026 ​(d)t=-2.075   ​(a) For t=2.092​, should you reject or fail to reject the null​ hypothesis?     A. Reject H0​, because t<2.057.   B. Fail to reject H0​,because t>2.057.   C. Reject H0​,because t>2.057.   D. Fail to reject H0​, because t<2.057.   (b) For t=0​, should you reject or fail to reject the null​ hypothesis?   A. Reject H0​,because t<2.057   B. Fail to reject H0​,because t<2.057.   C. Reject H0​,because t>2.057.   D. Fail to reject H0​, because t>2.057.   ​(c) For t=2.026​, should you reject or fail to reject the null​ hypothesis?     A. Fail to reject H0​, becauset>2.057.   B. Fail to reject H0​,because t<2.057.   C. Reject H0​,because t<2.057.   D. Reject H0​, because t>2.057.

Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test.   H0: p=0.87 versus H1: p≠0.87 n=500, x=430 , a=0.1

Scores on a dental anxiety scale range from 0 (no anxiety) to 20 (extreme anxiety). The scores are normally distributed with a mean of 11 and a standard deviation of 4. Find the z-score for the given score on this dental anxiety scale. 16 Z16 (Type an integer or a decimal.)

What is the appropriate conclusion for this test? (Do not reject OR reject) H₀ and conclude that there (is or is not) sufficient evidence that mice with an average life span of 32 months will live to be (less or greater) than 42 months old when​ 40% of the calories in their diet are replaced by vitamins and protein.

Use technology to find the​ P-value for a​ right-tailed test about a mean with n=15 and test statistic t=1.293.   ​P-value≈? ​(Round to four decimal places as​ needed.)

Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test.   H0: p=0.79 versus H1: p≠0.79 n=500, x=390, a=0.01

3042 You'd like to test the null hypothesis that the means of the two samples (column A and column B) are the same. The alternative hypothesis is that they are not the same. You have no reason to believe that the standard deviations of the two samples are equal.  Test at the alpha = 0.10 level.   After using Excel, what do you conclude? Are the means the same? Group of answer choices You cannot reject the null hypothesis. Therefore, you conclude that the means of the two populations are the same. You cannot reject the null hypothesis. Therefore, you conclude that the means of the two populations are different. You reject the null hypothesis. Therefore, you conclude that the means of the two populations are different. You reject the null hypothesis. Therefore, you conclude that the means of the two populations are the same.   X1 X2 97.88 98.66 105.98 102.29 96.01 111.40 99.70 106.15 96.96 100.10 99.80 104.89 92.73 99.24 106.30 104.79 97.90 101.51 95.04…

State whether the standardized test statistict indicates that you should reject the null hypothesis. Explain. (a) t=2.242 (b) t= 0 (c) t=2.195 (d) t= -2.254 0. (a) For t 2.242, should you reject or fail to reject the null hypothesis? O A. Reject Ho, because t> 2.219. O B. Reject Ho, because t 2.219. O D. Fail to reject Ho, because t<2.219.

Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test.   H0: p=0.77 versus H1: p≠0.77 n=500, x=380, a=0.1

What is the critical t score if you are testing a one-tailed hypothesis, α level of .05 with df = 36?   a. 1.671   b. 2.026   c. 2.028   d. 1.697