Starting from methane and butane make the following diene. You must use either methane and/or butane for all of your carbons, but you may use any other reagents you wish. CH4 + H3C- -CH3
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- Alcohols are important for organic synthesis, especially in situations involving alkenes. The alcohol might be the desired product, or the OH group might be transformed into another functional group via halogenation, oxidation, or perhaps conversion to a sulfonic ester derivative. Formation of an alcohol from an alkene is particularly powerful because conditions can be chosen to produce either the Markovnikov or non-Markovnikov product from an unsymmetrical alkene. Using your reaction roadmap as a guide, show how to convert 4-methyl-1-pentene into 5-methylhexanenitrile. You must use 4-methyl-1-pentene and sodium cyanide as the source of all carbon atoms in the target molecule. Show all reagents needed and all molecules synthesized along the way.39. Which of the following reactions will produce the highest percentage yield of 1-butene. C,H5OK*/C,H;OH A. CH;CH2CH(N*(CH3);)CH3 alc. KOH B. CH3CH2CHCICH3 conc. H2SO4 С. CH;СНОНСH-CH; heat NaOC,H5 D. CH3CHBrCH2CH3 СН,ОНDraw the major organic product formed by reaction of 2-hexyne with the following reagent: H₂O in H₂SO4 / HgSO4. • Consider E/Z stereochemistry of alkenes. • In cases where there is more than one answer, just draw one. • If no reaction occurs, draw the organic starting material.
- Draw structural formulas for the major organic product(s) of the reaction shown below. LOH + CH3CCI **** AICI 3 You do not have to consider stereochemistry. • If no reaction occurs, draw the organic starting material. • Remember to include all of the formal charges on the atoms of any nitro groups. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the Separate multiple products using the + sign from the drop-down menu. 4Draw the structure for an alkene that gives the following reaction product. 7 CH2l2, Zn/Cu Ignore alkene stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. / [F ?i the 1- propene with one molecule chlorine by using CH2C12 as catalyst result----- .A CH2CI-CH2-CH3 .B CH2CI-CHCI-CH3 .C CH3-CHCI-CH2CI .D CH2CI-CH2-CH2CI
- Draw the product or products that will be obtained from the reaction of cis-2-butene and trans-2-butene with each of the following reagents. If a product can exist as stereoisomers, show which stereoisomers are formed. 1. HCl. 4.Br2 in CH2Cl2 7. H2O + H2SO4 2. BH3/THF, followed by HO-, H2O2, H2O 5. Br2 + H2O 8. CH3OH + H2SO4 3. a peroxyacid 6. H2 + Pd/C[Review Topics] Draw structural formulas for the major organic product of the reagents shown. CH3 CH3 HNO3 H₂SO4 • You do not have to consider stereochemistry. Apply formal charges to any nitro groups. • If there is more than one major product possible, draw all of them. • Separate multiple products using the + sign from the drop-down menu. ChemDoodle Sn [FAn alkene having the molecular formula C11H20 is treated sequentially with ozone (O3) and zinc/acetic acid to give the product/s shown. CH;CH2ČCH,CH3 Draw a structural formula for the alkene. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. In cases where there is more than one answer, just draw one. C opy aste ChemDoodle
- reaction the 1- butene with one molecule chlorine by using water as catalyst resul1 .A CH2CI-CHCI-CH2-CH3 .B CH2CI-CHCI-CH2-CH3 .C CH2CI-CHOH-CH2-CH3 .D CH2OH-CHCI-CH2-CH3for this question. Draw a structural formula for the missing product in the following reaction. 0. NaHCO3 H20 ? + CO2 + H20 + CH3C-OH • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Include cationic counter-ions, e.g., Na+ in your answer, but draw them in their own sketcher. C P. opy aste [F **** C - Visited CH4 ChemDoodle Retry Entire Group 5 more group attempts remaining Submit AnswerName the alkene. Be sure to indicate stereochemistry and use hyphens (-) not endashes (-). H2C–CH3 H. H2C-HC CH3 H3C The alkene is named: