STARTING AMOUNT X A cup of coffee contains 95.0 milligrams of caffeine. How many grams is this? ADD FACTOR x ( ) == ANSWER RESET 10 9.50 x 106 9.50 x 10 0.01 9.50 × 104 9.50 x 10-6 9.50 W 9.50 × 10-3 0.001 9.50 × 10-4 0.0950 0.950 100 0.1 + 1 10-6 10% 1000 95.0 САРС mg g 5:51 PM

A solution was created by dissolving 7.399 g of calcium chloride in 54.2 mL of water (d = 1.00 g/mL). What is the boiling point of this new solution? The ko for water is 0.52°C/m. The boiling point of pure water is 100.0°C. Round your answer to 2 decimal places.

The following common units expressing parts per million (ppm) in weight per weight (w/w) or mass per mass (m/m) are the following EXCEPT: O mg/Kg O none of the above O ng/mg O ug/g

What do the abbreviations in the equations below mean?  (write next to the equations)   C  +  MU  =  R   C%  +  MU%  =  100%   MU%  =    MU   × 100%                      R     C%  =   C   × 100%    R

STARTING AMOUNT X A particular beer is 6.50 % ethanol by volume (C₂H₂O). If a single bottle of beer contains 750.0 mL of beer, what mass, in g of ethanol (C₂H₂O), is present in the bottle? The density of ethanol is 0.789 g ethanol/mL ethanol 3.85 6.18 ADD FACTOR x( ) 61.8 0.385 6.50 Question 16 of 24 0.001 9.10 × 104 38.5 10 ANSWER 0.01 1 %v ethanol mL ethanol mL ethanol/mL beer 0.789 750.0 g ethanol RESET 3 0.1 100 mL beer 1000 0.618 Submit +

- 1 A certain liquid X has a normal boiling point of 95.40 °C and a boiling point elevation constant K,=0.75 °C•kg•mol A solution is prepared by dissolving some zinc chloride (ZNCI,) in 400. g of X. This solution boils at 96.5 °C. Calculate the mass of ZnCl, that was dissolved. Round your answer to 2 significant digits. olo Ar x10 ?

What is the equation of the line when the data in the table below is plotted? Mass is the independent variable and volume is the dependent variable. Mass (g) Volume (ml) 1.023 2.8 2.043 5.5 3.001 8.1 3.997 10.8 What is the mass of a 3.5 ml sample? How well does the curve fit the data (how do you know)?

Give Hand written answer

PLEASE SEE IMAGE ATTACHED

Use the References to access important values if needed for this question. It is often necessary to do calculations using scientific notation when working chemistry problems. For practice, perform each of the following calculations. (3.10 × 10-5) (1.00 × 10-8) 10-8)=[ 3.55 × 104 2.75 x 10-4 7.55 × 105 (3.10 × 10-5) (2.75 × 10-4) 3.55 × 104