Please draw the hashtable • Start with an empty hash table of capacity 10 and load factor .75• Double the table capacity during a resize operation.• The hash function maps String keys to indexes using the first character base 26 mod table size.• Example: "Wilson"• Use quadratic probing to resolve collisions. Ex. h(n), h(n) + 1?, h(n) + 2², h(n) + 3² + .. (mod table22 mod 10 = 2size)• Show the final table after adding the following in this order: "Schmitt", "Cernan", "Duke","Young", "Irwin", "Scott", "Mitchell", "Shepard", "Bean", "Conrad", "Aldrin", “Armstrong"For your convenience here are character/number mappings:А в с D E F G н IJK L M0 134 5 6 7 89101112N o P QR ST U Vw x Y Z13141516171819202122232425

Start with an empty hash table of capacity 10 and load factor .75 • Double the table capacity during a resize operation. • The hash function maps String keys to indexes using the first character base 26 mod table size. • Example: "Wilson" • Use quadratic probing to resolve collisions. Ex. h(n), h(n) + 1², h(n) + 2?, h(n) + 3² + ... (mod table 22 mod 10 = 2 size) • Show the final table after adding the following in this order: "Schmitt", "Cernan", "Duke", "Young", "Irwin", "Scott", "Mitchell", "Shepard", "Bean", "Conrad", "Aldrin", "Armstrong" For your convenience here are character/number mappings: в с D E F G нI кLм 5 6 7 8 9 1 2 3 4 10 11 12 O P Q R S IU v w x Y Z 13 14 15 16 17 18 19 20 21 22 23 24 25

Start with an empty hash table of capacity 10 and load factor .75 • Double the table capacity during a resize operation. • The hash function maps String keys to indexes using the first character base 26 mod table size. • Example: "Wilson" • Use quadratic probing to resolve collisions. Ex. h(n), h(n) + 1², h(n) + 2?, h(n) + 3² + ... (mod table 22 mod 10 = 2 size) • Show the final table after adding the following in this order: "Schmitt", "Cernan", "Duke", "Young", "Irwin", "Scott", "Mitchell", "Shepard", "Bean", "Conrad", "Aldrin", "Armstrong" For your convenience here are character/number mappings: в с D E F G нI кLм 5 6 7 8 9 1 2 3 4 10 11 12 O P Q R S IU v w x Y Z 13 14 15 16 17 18 19 20 21 22 23 24 25

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The hash table array has capacity of 10. Capacity is the number of slots present in the array that is used to build the hashtable. The hash function returns the absolute value of the key mod the capacity of the hash table. a) Insert these keys in the hash table: 3,23,11,21,1,7,77,8 where the hash table uses quadratic probing to resolve collisions. b) Search and Delete 3 and 11 from the table. Be careful about changing the status of the table slot to “deleted” after deleting each item. c)Search 23 and 21 from the table and print their position.
3. Double hashing is one of the methods to resolve collision. Write a function to implement this method. The equations used in this method are given below. Note: implement everything within the double hash function. P = (P + INCREMENT(Key)) mod TABLE_SIZE INCREMENT(Key) = 1 + (Key mod INCR)
Course: Data Structure and Algorithms Language: Java Kindly something and Answer in 1 hour. Read Carefully and give answer with all necesary details. See the image for askii codes. Question6: In this Problem, you are required to insert some keys into a hash table, using given hash functions. You have to Draw a Hash table with the inserted keys. Write total number of collisions encountered when a particular collision resolution technique is used. size= 13, H(X) = sum of Ascii codes of key % HTSIZE Keys: Mia, Bea, Zoe, Jan, Ada, Sam, Leo, Meo, Ben, Tim, Ted, Zod Use Linear probing: H’(X) = [H(X) +f(i))] % HTSIZE where f(i)=i where i=0,1,2,….
Draw the contents of the hash table given the following conditions: The size of the hash table is 25. • Linear Probing is used to resolve collisions. • The hash function H(k) should be calculated in the following way where k is the element to be hashed: R(k) = k mod (summation of last two digits of your student id + 7) If R(k)<10 H(k)=R(k) + 8 else H(k)=R(k) - 4 What values will be in the hash table after the following sequence of insertions? 55, 65, 8, 18, 20, 11, 56, 27, 15, 167 [Note: Draw the values using a hash table and show your work for partial credit.]
3. Implement quadratic probing, double hashing, and linear probing. Compare them with two criteria: 1) number of collisions, 2) average probe length (probe length: how many tries to find an empty slot; average probe length: total probe length divided by total number of items in the hash table. Summarize the comparison into a table or a plot
Task - 1: Write a java program to implement the following algorithms for Open Addressing techniques for Hash Table data structure. (Use a simple array of integers to store integer key values only). HASH-SEARCH(T, k) HASH-INSERT (T, k) i = 0 repeat j = h (k, i) if T[j] == NIL T[j] = k return j else i = i + 1 ● i = 0 repeat until i == m error “hash table overflow" For both algorithms, to compute the index j, write the following methods: getLinear ProbIndex (key, i) getQuadraticProbIndex ● get DoubleHash (key, i) (key, i) j = h (k, i) if T[j] == k return j i = i + 1 until T[j] == NIL or i = m return NIL Linear Probing index is computed using following hash function: h(k, i) = (h₁(k) + i) mod m h₁(k)= k mod m Quadratic probing index is computed using following hash function: h(k, i) = (h₁(k) + i²) mod m h₁(k)= k mod m Double hashing index is computed using following hash function: h(k, i) = (h₁(k) + i h₂(k)) mod m h₁(k)= k mod m h₂(k) = 1 + (k mod m - 1)
Draw the contents of the hash table given the following conditions: • The size of the hash table is 18. • Linear Probing is used to resolve collisions. • The hash function H(k) should be calculated in the following way where k is the element to be hashed: R(k) = k mod (summation of last two digits of your student id) If R(k)<10 H(k)=R(k)+8 else H(k)=R(k)-2 What values will be in the hash table after the following sequence of insertions? 35, 18, 8, 13, 11, 49, 16, 27 [Note: Draw the values using a hash table and show your work for partial credit.]
Problem 5 ( ,. Suppose that your hash function resolves collisions using open addressing with double hashing, which we discussed in the class. The double hashing method uses two hash functions h and h'. Assume that the table size N = 13, h(k) = k mod 13, h '(k) = 1 + (k mod 11), and the current content of the hash table is: 0 1 2 3 4 5 6 7 8 9 10 11 12 28 98 59 22 43 51 If you insert k = 15 to this hash table, where will it be placed in the hash table? You must describe, step by step, how the location of the key is determined.
A collision occurs in hashing when: O a. two data items hash to the same location. O b. a data item hashes to two locations O c. the table is full O d. the hash function is undefined for a given data item. O e. None of these are correct
2. Implement the hash table for the following elements: a. 22,32,45,67,89,9 Use Double hashing technique to handle the collision. [ hash1(key)=key%10, hash2(key)=PRIME- (key%PRIME) ].
Class HashTable: Implement a hash table to store integers (including negative ones). stored in the table int[] data. Use the hash function: h(x) = (x · 701) mod 2000. The table size is 2000. Ensure non-negative indices between 0 and 1999. Implement the following methods: insert(int key): Inserts the integer into the table. Returns true if successful, false if the element is already in the table. search(int key): Searches for the integer in the table. Returns true if found, false otherwise. delete(int key): Deletes the integer from the table. Returns true if successful, false otherwise. Class HashTable2: Implement a second hash table using a different hash function and collision resolution strategy. Keys are integers (including negative ones). Use the hash function: ℎ(�)=(�⋅53)mod 100h(x)=(x⋅53)mod100. The table size is 100. Ensure non-negative indices between 0 and 99. Implement the following methods: insert(int key): Inserts the integer into the table. Returns true if…
in c++ Create a student hash table that contains information, studentID (int), name (string), marks_oop345 (float). The size of hash table is equal to the number of students in the class. Use linear probing in case of collisions. Perform insertion, deletion, display and search operations.