= Question 3. In the following hash table, we insert elements using hashing with open addressing with quadratic probing. Elements have as keys integer numbers, and the hash function for the i-th probe is given by hash(x, i) = (x + ²) %11. We insert, in the given order, the elements with the following keys: 46, 58, 57, 39. Indicate, where these elements will be placed in the table. index value 0 1 2 3 4 5 6 7 8 9 10

= Question 3. In the following hash table, we insert elements using hashing with open addressing with quadratic probing. Elements have as keys integer numbers, and the hash function for the i-th probe is given by hash(x, i) = (x + ²) %11. We insert, in the given order, the elements with the following keys: 46, 58, 57, 39. Indicate, where these elements will be placed in the table. index value 0 1 2 3 4 5 6 7 8 9 10

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Q4) following sequence of keys is to be inserted: 25 77 0 23 3 15 Insert these keys using each of the following approaches. If overflow occurs, say so, and indicate the element that causes the overflow. You are given an empty hash table of size 7 that uses open addressing. The a. h(x) = x % 7; linear probing b. h(x) = x % 7; quadratic probing 1 2 3 3 4 61 2. 6.
Question 7 Write a program, which returns the index of the minimum repeating element of the array in Jinear time and does just a single traversal of the array. You should use hash table functions like a hash set, hash map, etc. Ardil Subarray arrli+1...n-1] Return index ASAP duplicate is found The implementation can be seen here and requires Qn2) time, where n is the size of the input The idea is to traverse the array from right to left. If the element is seen for the first time insert it into the set; otherwise, update the minimum index to the element's index. Input: {5, 6, 3, 4, 3, 6, 4 } Output: The minimum index of the repeating element is 1 Input: {1 2, 3, 4, 5, 6 } Output: Invalid Input
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