ssume the data in $s0 = O×1234ABCD, the data in Şa0 = 0×1234ABCD. After executing the follo sembly code, what are the data stored in $sland $s2 represented in hexadecimal format. b $s0 0 ($a0) b $s10 (Sa0) bu $s2 0 (Sa0)
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- Stream manipulator showpoint forces floating-point values to print with the default sixdigits of precision unless the precision value has been changed, in which case floatingpoint values print with the specified precision. T/FIn executing the following code: START: MOV CX, 0002 MOV SI, 0300 MOV DI, 0302 LOOP: MOV AL, (SI) XOR (DI), AL INC SI INC DI DEC CX JNZ LOOP HLT with the following byte contents: (0300H) = OAH, (0301H) = OBH, (0302H) = 11H, (0303H) = 21H. The result will be:Edit this program so that it returns ecg data instead of heart beat in BPM. #include <ArduinoBLE.h> #define BLE_UUID_HEART_RATE_SERVICE "180D"#define BLE_UUID_HEART_RATE_MEASURMENT "2A37"#define ECG_SERV_UUID 0x2D0D#define ECG_MEAS_UUID 0x2D37#define ECG_NUM_CHANS_UUID 0x2D38#define ECG_SAMPLE_SETS_UUID 0x2D39#define ECG_COMMAND_UUID 0x2D3A #define HRM_VALUE_FORMAT_8BIT 0#define HRM_VALUE_FORMAT_16BIT 1#define HRM_SENSOR_CONTACT_NOT_DETECTED ( 2 << 1 )#define HRM_SENSOR_CONTACT_DETECTED ( 3 << 1 ) typedef struct {uint8_t flags;uint8_t heartRate;} heart_rate_measurment_t; union heart_rate_measurment_u{struct {heart_rate_measurment_t values;};uint8_t bytes[ sizeof( heart_rate_measurment_t ) ];}; union heart_rate_measurment_u heartRate = { .values = { .flags = 0, .heartRate = 0 } }; #define BLE_DEVICE_NAME "Arduino HRM"#define BLE_LOCAL_NAME "Arduino HRM" BLEService heartRateService( BLE_UUID_HEART_RATE_SERVICE );BLECharacteristic heartRateCharacteristic(…
- Suppose Pep/9 contains the following four hexadecimal values: A: 19AC X: FE20 Mem[0A3F]: FF00 Mem[0A41]: 103D What are the four hexadecimal values after the following statement executes? 690A3F12. If A=10010101. Then what will be the value in 'A' after execution of (a) RR A (b) RL A (c) SWAP AIn executing the following code: MOV CX, 0002 START: MOV SI, 0300 MOV DI, 0302 LOOP: XOR (DI), AL INC SI MOV AL, (SI) INC DI DEC CX JNZ LOOP HLT with the following byte contents: (0300H) = 0AH, (0301H) = OBH, (0302H) = 11H, (0303H) = 21H. The result will be: Select one: a. (0300H) = 0AH, (0301H) = OBH, (0302H) = 1AH, (0303H) = 2BH (0300H) = 0AH, (0301H) = OBH, (0302H) = 10H, (0303H) = 20H b. c. (0300H) = 0AH, (0301H) = OBH, (0302H) = 1AH, (0303H) = 20H d. None of the options given here e. (0300H) = 0AH, (0301H) = OBH, (0302H) = 1BH, (0303H) = 2AH
- variable1 DWORD 14253647h Assuming that the computer uses little endian order, illustrate how 'variable1' is stored in the memory. Answer format: For the following example, variable1 D WORD 14253647h If you think 14 goes to 0-th byte and 25 goes to 1st byte, you can write answer as follows: Offset (i-th byte) : value 0:14 1:25 Paragraph B IIIA set of current readings is stored in memory locations starting at XX50H. The end of the data string is indicated by the data byte 00H. Add the set of readings. The answer may be larger than FFH. Display the entire sum at PORT1 and PORT2 or store the answer in the memory locations XX70 and XX71H. Data(H) 32, 52, F2, A5, 00Q14: The function f(x) = e can be represented in a Taylor series by: ex = -Σ n! 72=0 Write a program in a script file that determines e by using the Taylor series representation. The program calculates e by adding terms of the series and stopping when the absolute value of the term that was added last is smaller than 0.0001. Use the program to calculate e², e05 and eª This problem can be solved by using while - end loop because : ONumber of passes not known OIt is a Taylor series All of the given O Number of passes is predetermined O Estimated error value must be calculated
- In this lab, you will determine the least common multiple (LCM) of two numbers in memory named datax and datay. The calculated LCM value should be stored in the area of memory directly following the given data. To calculate the LCM, you can first find the greatest common divisor (GCD) of the two numbers and use the formula LCM(xy)*GCD(x,y) = x*y. To find the GCD, you can use Dijkstra's Algorithm to forgo the use of division or modulus functions. Pseudocode (C code) for Dijkstra's Algorithm used to find the GCD is as follows: int GCD(int x, int y) { if(x == y) return x; else if(x > y) return gcd(x-y, y); else return gcd(x, y-x); } Notice that you are passing values in and out of subroutines, which is the focus of lecture this week. You may choose any of the 3 methods (pass by registers, reference, or stack) that you feel is most appropriate.Create a main() function for your program. The purpose of this function is to control the game logic for a Power Quiz game. The steps of this game are as follows: Set the user's score to 0. ● Generate a random integer n in the range [1,128] inclusive. Ask the user to enter the corresponding binary number for n. Use your binary_to_decimal() function to find the correct answer. Check if the user's answer is correct or not O If correct, add 1 to their current score O If not, tell them the correct answer. Repeat these steps until the user types "stop" in place of a number. If the user types "stop", your program should print out their final score and terminate the game. Finally, add the following code to the end of your program to make main() function work. Note those '' are two underscores '__'. if name main() Print == 11 '___main__": Activity DetailsHEMIP INTEGER THROUGH CODEV.