Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Given: Metal Specimen diameter x-section (circular)= 0.55 in
Gage Length= 2.030 in
Fracture bccurved at 28,500 pounds
Final length= 2.30 in
Final diameter= 0.43 in
Determine: a) Ultimate tensile stress in ksi
b) Elongation as a percentage
c) Reduction of a x-sect. area as a percentage
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- A) An engineer works for a company that has many gray cast iron rods of different diameters and would like to design an equivalent rod that could handle a force of P= 10.0 kipkip without fracturing. What is the minimum diameter that this new rod must have to support P? B)A tensile test is being conducted on a steel-rod specimen with a gauge length of L0 = 4.0 in and an initial diameter of d0 = 0.75 in. If the final length of the rod at fracture is Lf= 5.53 in , find the percent elongation of the rod at fracture.arrow_forwardSpecimen (Rebar) Original Length Length when it was clamped Diameter (mm) Internal Diameter (mm) External 1 300 mm 163mm 10 15.030 2 300 mm 180 mm 10.020 14.386 3 300 mm 197mm 9.40 15.028 Dimension of Specimen Specimen A0 P max Tensile strength Modulus of elasaticity Percent Elongation 1 474 N 179.381 2.776 MPa 19.76 MPa 13.4% 2 475 N 159.070 2.895 MPa 18.74 MPa 16.67% 3 485 N 179.381 2.706 MPa 20.058 Mpa 13.4% Result of testing Observation What is the possible discussion of these tablesP.S THIS IS NOT GRADED, ITS JUST EXAMPLESarrow_forwardThe modulus of rigidity (shear modulus) of a circular Cast Iron specimen subjected to a torsion test is: During Elastic Zone Angle of twist (°) TD Specimen Torque (N.m) Specimen T = 2) Radius Length 2.5 15 rp 3 mm 50 mm 10.8 20 Select one: O a. 13.586 GPa. O b. 236.73 GPa. O c. 236.73 MPa. O d. 88.39 GPa. web.whatsapp.com. now +961 76 301 678 balorfo 9-20 DMarrow_forward
- Ql- mm ,length 40 mm. The final diameter 18 mm and length 45 mm. Draw the force-extension diagram and determine the following : a) Ultimate tensile strength, c) Modulus of elasticity, d) Percent elongation and e) Percent reduction in area. The following data collected from tensile test of a metal bar diameter 20 b) The fracture strength, Force - kN 75 90 | 105 120 131 125 110 25 50 4.7 Extension-mm 0.02 0.04 0.06 0.20 - 0.60 1.60 3.00 4.0 Fracturearrow_forwardBased upon the information in the table below, which material is the stiffest? Elastic Strain at Fracture Fracture Yield Strength (MPa) Tensile Modulus Strength (MPa) 120 550 340 Fractures before yielding 850 Strength (MPa) 105 500 265 650 720 Material 100 415 310 0.40 0.15 0.23 (GPa) 150 310 210 350 210 700 0.14 OE OB A. ODarrow_forwardThe following data are obtained from the Charpy impact test of a copper specimen. a) Length of the square cross-section specimen = 70 mm b) Each side (top & bottom) of the cross-section = 9.64 mm c) V - Notch thickness at middle of the specimen length = 1.06 mm d) Impact Strength = 279 kJ/m? Determine the Cross-sectional area at the top surface, Cross-sectional area at notch & Impact energy of the copper specimen. Solution: 1. Cross sectional area at the top surface 92.9296mm^2 2. Cross-sectional area at notch 82.7112mm^2 3. Impact Energy 23.0764248Jarrow_forward
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