Solve the initial value problem. dy 4x²-x-2 x2 = (x+1)x=27), y(1)=2 dx (x + 1)(y + 1) ' Begin by separating the variables. Choose the correct answer below. A. (y + 1)dy = O B. O C. 4x²-x-2 2 x²(x+1) x²(x+1) 2 4x -x-2 dy dx -dy= = 1 +1 2 4x²-x-2 -dx dx 2 x(x + 1)(y + 1) D. The equation is already separated. The solution is (Type an implicit solution. Type an equation using x and y as the variables.)

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter1: Equations And Inequalities
Section1.CR: Chapter Review
Problem 67E: 67. Calculate the discriminant associated with the equation 6x2+5x+1=0.
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Solve the initial value problem.
dy
4x²-x-2
x2 = (x+1)x=27), y(1)=2
dx (x + 1)(y + 1) '
Begin by separating the variables. Choose the correct answer below.
A. (y + 1)dy =
O B.
O C.
4x²-x-2
2
x²(x+1)
x²(x+1)
2
4x -x-2
dy
dx
-dy=
=
1
+1
2
4x²-x-2
-dx
dx
2
x(x + 1)(y + 1)
D. The equation is already separated.
The solution is.
(Type an implicit solution. Type an equation using x and y as the variables.)
Transcribed Image Text:Solve the initial value problem. dy 4x²-x-2 x2 = (x+1)x=27), y(1)=2 dx (x + 1)(y + 1) ' Begin by separating the variables. Choose the correct answer below. A. (y + 1)dy = O B. O C. 4x²-x-2 2 x²(x+1) x²(x+1) 2 4x -x-2 dy dx -dy= = 1 +1 2 4x²-x-2 -dx dx 2 x(x + 1)(y + 1) D. The equation is already separated. The solution is. (Type an implicit solution. Type an equation using x and y as the variables.)
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