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Find an equation of the plane. The plane through the point (3, 0, 4) and perpendicular to the line x = 7t, y = 3-t, z = 5 + 6t

Find an equation of the plane. The plane through the point (3, 0, 4) and perpendicular to the line x = 7t, y = 3-t, z = 5 + 6t

Trigonometry (MindTap Course List)
Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
ChapterP: Prerequisites
Section: Chapter Questions
Problem 15T
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Question
Find an equation of the plane. The plane through the point (3, 0, 4) and perpendicular to the line x = 7t, y = 3-t, z = 5 + 6t
Transcribed Image Text:Find an equation of the plane. The plane through the point (3, 0, 4) and perpendicular to the line x = 7t, y = 3-t, z = 5 + 6t
Expert Solution
Step 1

The equation of line which is perpendicular to the plane is given as x=7t, y=3-t and z=5+6t.

So,

a= 7, b=-1 and c=6.

The point on the plane is given as (3,0,4).

x1=3, y1=0, and z1=4.

 

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