Solve the following problem: A 0.9471 g sample containing dimethylphthalate, C6H4(COOCH3)2 (194.19 g/mol) and non-reactive chemical species was heated by reflux with 50.00 mL of 0.1215 M NaOH to hydrolyze the ester groups (this process is called saponification). C6H4(COOCH3)2 + 2OH- → C6H4(COO)22- + 2CH3OH After the reaction was complete, the excess NaOH was back-titrated with 24.27 mL of 0.1644 M HCl. Calculate the percent dimethylphthalate in the sample.
Solve the following problem: A 0.9471 g sample containing dimethylphthalate, C6H4(COOCH3)2 (194.19 g/mol) and non-reactive chemical species was heated by reflux with 50.00 mL of 0.1215 M NaOH to hydrolyze the ester groups (this process is called saponification). C6H4(COOCH3)2 + 2OH- → C6H4(COO)22- + 2CH3OH After the reaction was complete, the excess NaOH was back-titrated with 24.27 mL of 0.1644 M HCl. Calculate the percent dimethylphthalate in the sample.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve the following problem:
A 0.9471 g sample containing dimethylphthalate, C6H4(COOCH3)2 (194.19 g/mol) and non-reactive chemical species was heated by reflux with 50.00 mL of 0.1215 M NaOH to hydrolyze the ester groups (this process is called saponification).
C6H4(COOCH3)2 + 2OH- → C6H4(COO)22- + 2CH3OH
After the reaction was complete, the excess NaOH was back-titrated with 24.27 mL of 0.1644 M HCl. Calculate the percent dimethylphthalate in the sample.
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