Solve the circuit with nodal analysis and find I, and Vy. Vs, =-4V Vy Vs, =10V Is,=1A wyoh=2 Rq =5ohm Is =-2A
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Q: 4. In a short circuit analysis, the bases chosen are 34.5 kV and 100 MVA. Find the impedance base.
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Q: CONVERT AND GRAPH THE FF: I. Rectangular to Sphericcal 1. (5, 4, -9) 2. (-3, 3, 7) 3. (6, -8, 10)
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- Need to use kirchhoffs voltage and circuit laws. But not understanding. Need to find V500,V50,V150,V250,V1000,P1000.-The Vollage V= 100210°V is 62 pplied across a capacilive 1oad . The 1-a kes ap paraal' Power Load of 500VA teading Power fracl-or. The reaclance (xc) of load 's---- 7TE is given as RI-102, Rz=7L, Xes= 10R, Xez=52. XM=6R, Xc=71 in the circuit below. Calculate I. curment and Ve voltage in polar form and mork then the following ilems. in in Angles are given in degr ees. I, JXL1 R2 100/60° jXM -jXc +Vc a) Vo 29.696/17.552 b) Ve 25.870/25.402 Ve 14.702/10.440" d) Vo 27.661/177.887° 1.908,/62 552" 1.805/27,130 4.058/17.003" 21.808/22.713" h) Ve 3.352,/17.887" 2.446/9.456
- . For the circuit shown in figure. For the circuit shown 16ke Rc 18V in Figure. If VeE =-|4V -14v RB Vec=18 V, VeE = 8 V, I8= 8MA, B= 100 %3D The value of RB is Kohm. . * ... ... ......hetee to the series ciecuit Given: RT series Ciecuit t=\.5KR R1=500 below and I =50MA %3D Find Rz, VT, VieVz oVí fFor the circuit diagram in figure Q22: which of the following is the total impedance? 12 Ri 10R R2||5R Figure Q22 V 220V40 50HZ L1 315mH C1=350uF O a. 3.33/0° O b. 4.71290°2 O c. 7.3304-19.66° O d. 10.37261.19°2
- Solve the power triangle at Z6 in the circuit diagram below.V1, V2, and V3 = 220∠0°, 50 HzZ1 = 7+j8 ohmsZ2 = 6+j3 ohmsZ3 = 5+j5 ohmsZ4 = 2+j3 ohmsZ5 = 8+j4 ohmsZ6 = 1+j9 ohmson For the circuit in Figure 1. If R = 500 and XL = 200, Find ZT and 0₁ e Figure 1 OA. B. C. D R a. 53.850 angle -68.2deg a. 53.850 angle +68.2deg a. 53.850 angle +21.8deg a 53 angle -21.8deg LG16 >e Find. To using symmetvic and Skew symmetric concepts. R Ri R 1₁=9 R R₁ R₂ R 20
- DC-AC Circuits Express R1 using Rx, Ry, and Rz when performing wye to delta conversion R3 Rx Rz R2 R1 Ry O A. (Rx+Ry)(Ry+Rz)(Rx+Rz) Rx В. RyRz Rx+Ry+Rz O C. Ry+Rz RXRYRZ O D. RXRYRZ Ry+Rz OE. RxRy+RyRz+RXRZ RxAdpole having anomentp=3-5ŷ +lont nc m is located at Q(ir3)-4jinfveespa.ce Find uet pase)Find the voltage and current across R,L,C Include phasor diagrams and impedance triangle