デジタル形式で段階的に解決ありがとう!!SOLVE STEP BY STEP IN DIGITAL FORMATWrite the products of the following reactions, if there is more than one product,enter them and indicate which is the majority and if the compounds presentstereochemistry, it must be entered appropriately.EXPLAIN THE REACTION MECHANISM STEP BY STEPNHANH,d=CHNaOH+HO.OH

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Answered: デジタル形式で段階的に解決ありがとう!! SOLVE STEP BY…

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter10: Organohalides

Section10.SE: Something Extra

Problem 45AP

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(b) Write the mechanism for the formation of products in following reaction. Clearly show the intermediates in the reaction. Which product is a kinetically controlled and which one is the thermodynamically controlled product? CH3 CI. CI. A½O3, HCI H Ph-C=C-CH3 Ph CH3 Ph H.
7A Write the possible products of the following reactions, the mechanism by which they were formed. mentioning Br CH3OH CH3ONa
Provide the product and mechanism for the reaction: ОН Cro, H,SO, H,0
b) Refer to the following equation to answer Q3b (i), (ii) and (iii). CH3 H,SO, Н—с—он C-CH3 ? + H2O Но- ČH3 (i) Determine the product of the above reaction. (ii) Name the above reaction. (iii) Propose the mechanism for the above reaction.
2) Draw the MAJOR organic products for the following reactions, include stereochem where relevant and there may be more than one product if the reaction would not produce any product, then simply write no reaction in the box provided வி OH Har, High Temp HB, Low Temp Na, CH₂OH 1. R₂BH 2. H₂O₂, NaOH 3
Peroxides are often added to free-radical reactions as initiators because the oxygen–oxygen bond cleaves homolytically rather easily. For example, the bond-dissociation enthalpy of the O¬O bond in hydrogen peroxide (H¬O¬O¬H) is only 213 kJ>mol (51 kcal>mol). Give a mechanism for the hydrogen peroxide-initiated reaction of cyclopentane with chlorine. The BDE for HO¬Cl is 210 kJ>mol (50 kcal>mol).
20. Identify the product for each step in the following reaction sequence. Write complete equations showing the structure of all reactants and products for each step. (a) Isopropyl benzene + NBS/heat ---------->A (b) A+ t-BuOK ---------> B (c) B + 1)BH3 followed by 2)H2O2/NaOH -----> C (d) C + PCC ------> D
Neopentyl alcohol, (CH3)3CCH2OH, reacts with concentrated HBr to give 2-bromo2-methylbutane, a rearranged product. Propose a mechanism for the formation of thisproduct.
H11.38 - Level 2 Unanswered • 3 attempts left Which of the following reactions would NOT have a "proton transfer step" in the reaction mechanism: 2-bromo-2-methylbutane + A H2O →2-methyl-2-butanol 2-bromobutane + NaOH → (E)-2-butene 1-bromobutane + NaOMe → C methoxy butane 2-bromo-2-methylbutane + tert- butoxide → 2-methyl-1-butene
CH3 CH3 Br- Br2 CH2CI2 CH3 CH3 H3C H3C Br Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2C12. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 Br- .CH3 .CH3 H3C H3C :Br :Br:
Fill in the red box(es) with the missing reactant(s), reagent(s), product(s), solvent, and/or conditions and write a reasonable mechanism for the reaction. Not every box need be used and not every box necessarily corresponds to only a single species. If no reaction occurs OR no reagents exist to perform the reaction state, "NOT POSSIBLE" AND explain why. OH O,N "ON N(CH,CH,), Your Answer:
Suggest a mechanism for the following reactions. Each will require multiple types of concerted pericyclic reactions (cycloaddition, electrocyclic, and sigmatropic. Classify each reaction type. Me3Si Me3Si Me Si Me Sil g H

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