Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Solve I3 using source transformation
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- I-2A The load in the circuit in the figure current through resistance (RL) a- Using Norton's theorem b- Using Thevenin's theorem Find. R=7 RI=7 R,=20 R3-6 E- 5V -Ez - 7V Rz - 102 (IL =?)arrow_forwardRequirements: • Find Current R1 and R2 And find the voltage in R3 5. Superpositionarrow_forwardPROBLEM 4 Find Req R2 R3 120 40 R4 60 R5 R7: 260. R1 120 Reg R6 180 Figure 4arrow_forward
- Mathematics for Electrical Engineers Problem Set 6 Evaluate the following: 1 1 a. L-1 = -₁ | 1/2 + b. C-¹ [225] + + 25² 353 4s 4-2s s²+25 4-s² c. L-¹ s4+85² +16¹arrow_forwardSolve for the current thru R3 given R1-10k, R2-R4-5k, R3-15k, V1-V2-10V. R. R. V- 0.5 UA 10 UA 0.5 mA 10 mAarrow_forwardFind the state space equations for the circuit shown. Show full detail on each step of the KVL/KCL or Nodal and mesh. R1 Ve R2 R3 R4 C1 EC2 R5 L2arrow_forward
- For R1-35, R2=23, R3-16, R4=75, R5=42, R6=70, R7=47, R8-22, R9-47, R10-53 and I1=0.08 A in the circuit shown, calculate the following: I1( R10 R1 R9 www R& R7 3R6 R2 www R4 b) the power developed by the source= Oa. -0.084173676010289 Ob. 0.02805789200343 Oc. -0.14028946001715 Od. -0.02805789200343 R5 www {R3 2 a) the equivalent resistance was seen by the source = Oa. 10.96011406384 Ob. -17.536182502144 Oc. 21.920228127679 Od. -4.3840456255359arrow_forwardR148 R149 R150 If R148 is 18 Ohms, R149 is 13 Ohms, R150 is 25 Ohms, and there is 4 Amps flowing through R150, what is the current through R148? Please show 3 decimal places and don't include units in your answer (i.e. don't include A in your answer).arrow_forwardThe dynamic part of the state space representation of the following circuit with R₁ = 20 R₂ = 20 L₁ = 0.5H L₂ = 0.25H is O 1. O 2. None of the answers O 3. O 4. O 5. -4 M=1 = 0 R₁ ww -2 [22]=16² 0 0 -0.5 L₁ 5 2 4-6 +64 1₂ In -8 4-6 90+4 = 0 →→ 30 4+4 [²]+[+]¹ -0.25] [142] + [0.25] ¹ L₂ 1/12arrow_forward
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