Solve by Kirchhoff's laws the following circuits. a) Find the current through each of the resistors in the following circuit 14.0 V R, 1000 R - R, 1.000 R-2.000 SR₂ 2.00 (1 1.000 b) Find the currents over the resistors:
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- = Using Kirchhoff's rules, find the following. (₁ = 70.9 V, 8₂= 60.7 V, and 83 1 E₁ R₂ E₂ 4.00 ΚΩ www R₂ 3.00 ΚΩ d E₁ 2.00 ΚΩ www R₁ (a) the current in each resistor shown in the figure above (b) the potential difference between points c and f 79.1 V.)The voltage divider shown in the figure has a potential difference (V) between point A and B and a potential difference (VO) between points C and D. What is V FO? A B RM 2R O A. 2 OB. 4 O C.3 OD. S M 2R R :2R C DWhat is the value of Rin ohms such that the current through the 25 ohm resistance is zero amperes. 100 45 0 25 Q 100 V RO 20 Q Type your numencarswen pnc sumN 7:52 Et C S/10/2 99+ +
- In an electrical circuit four resistors are connected in parallel and their equivalent resistance is 50ohms. Find the value of each resistors if the currents through each impedance are 0.8, 0.4, 0.6 and 0.2 ampere.22 S2 spF 182 172 122Solve fore the currents of each resistor using Kirchoff's laws (Show complete solution PLS) Write legibly
- A lead wire and an iron wire are connected in parallel. Their respective specific resistances are in the ratio 49: 24. The former carries 80 percent more current than the latter and the latter is 47 percent longer than the former. Determine the ratio of their cross sectional areas ROUND OFF TO THE NEAREST HUNDRETHSUse Kirchhoff's Law to solve for the current passing through each resistor. Compare it with what you got from the PHET Simulation A D 392 www 6V E www F 192 www 292 352 www 9V B CConstruct the DC circuit in MULTISIM. What is the voltage across each resistor, current through each resistor and the DC power dissipated by each resistor
- Solve for the circuits unknowns in the picture belowWhich of the following statements regarding circuits are true? To find resistance in a parallel circuit, you must sum the individual resitances The direction of conventional current is the direction of positive charge flow. In a circuit, electrons flow from high potential energy (at the negative terminal) to low potential energy (at the positive terminal). When electricity is passed through a lightbulb, the electrons are 'used up' by the bulb. All voltages in a loop sum to 12V The current that flows into a resistor is the same as the current that flows out. To 'short circuit' something means there is an alternate path of less resistance for the current to flow. Switching on a light happens immediately because electrons move from the power source to the bulb incredibly quickly. A 'kilowatt-hour' is a unit of power, not energy.Find the voltage across each inductor for the given circuit using the voltage divider rule. VL1 +m= L₁=10mH Vs=100 V, 60 Hz VL2 +mm- L₂=14mH