SO2Cl2 (g)SO2 (g) + Cl2(g).The reaction is initiated, and the following data are obtained. Time (h) Ptotal (kPa)073 14.796 17.269 18.9012 19.9915 20.71 In order to use this data, you will need to separate out the pressure that is just due to SO2Cl2. Obviously at time 0, all the pressure is due to SO2Cl2. At time 3 hours some of the SO2Cl2 has decomposed and given rise to SO2 and Cl2 so the pressure of 14.79 is due to SO2Cl2, SO2 and Cl2. You can set up an expression to find x (the amount of SO2Cl2) that has decomposed in order to get the actual pressure due to SO2Cl2 at 3 hours. You will need to do this for each time. Make sure you are just getting the pressure of SO2Cl2 for each data point not the total pressure!

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Answered: SO2Cl2 (g)SO2 (g) + Cl2(g). The…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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SO₂Cl₂ (g)SO₂ (g) + Cl₂(g).

The reaction is initiated, and the following data are obtained.

Time (h) Ptotal (kPa)

3 14.79

6 17.26

9 18.90

12 19.99

15 20.71

In order to use this data, you will need to separate out the pressure that is just due to SO₂Cl₂. Obviously at time 0, all the pressure is due to SO₂Cl₂. At time 3 hours some of the SO₂Cl₂ has decomposed and given rise to SO₂and Cl₂ so the pressure of 14.79 is due to SO₂C_l2, SO₂ and Cl₂. You can set up an expression to find x (the amount of SO₂Cl₂) that has decomposed in order to get the actual pressure due to SO₂Cl₂ at 3 hours. You will need to do this for each time. Make sure you are just getting the pressure of SO₂Cl₂ for each data point not the total pressure!

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