A certain reaction is known to have an activation energy E=9.0 kJ/mol. Furthermore, the rate of this reaction is measured at 370. K and found to be 5.4 x 107 M/s. Use this information to answer the questions in the table below. Suppose the concentrations of all reactants is kept the same, but the temperature is lowered by 10% from 370. K to 333. K. How will the rate of the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is added, which has the effect of lowering the activation energy by 10%, from 9.0 kJ/mol to 8.10 kJ/mol. How will the rate of the reaction change? The rate will The rate will choose one choose one 0 ©

Deducing a rate law from initial reaction rate data Some measurements of the initial rate of a certain reaction are given in the table below. [N] [H] initial rate of reaction 0.335 M 2.47M 18.0M/s 0.335 M0.592M 1.03 M/s olo 0.521 M 2.47M 28.0 M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbol. rate = k|| Ix10 k = ||

Draw the order of reaction graphs (reaction rate vs the concentration) for [NO] and [H2]. Explain the difference between the two graphs

A certain catalyzed reaction is known to have an activation energy E= 11.0 kJ/mol. Furthermore, the rate of this reaction is measured at 296. K and found to be 1.1 × 10 M/s. Use this information to answer the questions in the table below. Suppose the concentrations of all reactants is kept the same, but the temperature is raised by 10% from 296. K to 326. K. How will the rate of the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is removed, which has the effect of raising the activation energy by 5%, from 11.0 kJ/mol to 11.6 kJ/mol. How will the rate of the reaction change? The rate will The rate will choose one choose one choose one stay the same rise about 5% rise more than 5% rise less than 5% fall about 5% fall more than 5% fall less than 5% V

A certain catalyzed reaction is Known to have an activation energy Ea=29.0 kJ/mol. Furthermore, the rate of this reaction is measured at 331 K and found to be 2.7× 10* M/s. Use this information to answer the questions in the table below. Suppose the concentrations of all reactants is kept the same, but the temperature is raised by 10% from 331 K to 364 K. How will the rate or the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is removed which has the eftect of raising the activation energy by 10%, from 29.0 kJ/mol to 31.9 kJ mol How will the rate or the reaction change?

Some measurements of the initial rate of a certain reaction are given in the table below. [₂] [H₂] initial rate of reaction 2.38M 1.39 M 0.140 M/s 10.8M 1.39 M 2.88 M/s 2.38 M 0.584 M 0.0588 M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbo rate = k ロ・ロ -0 Ś ? Continue k = X

Some measurements of the initial rate of a certain reaction are given in the table below. N2 H2 initial rate of reaction 0.506M 2.50M 0.906 M/s 0.506M 6.72M 6.55 M/s 0.195M 2.50M 0.349 M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbol.

Can someone please help with question 7

Some measurements of the initial rate of a certain reaction are given in the table below. [N₂] [H₂] initial rate of reaction 2.10M 1.53 M 0.225 M/s 0.345M 1.53 M 2.10M 3.20M rate = k [] 0.00607 M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 2 significant digits. Also be sure your answer has the correct unit symbol. k = 0 0.471 M/s x10 X 5

Some measurements of the initial rate of a certain reaction are given in the table below. [N-] N2 H2 initial rate of reaction 0.776M 2.20M 53.0M/s 0.362M 2.20M 11.5 M/s 0.776M 9.89M 1.07 x 10°M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbol. rate = k|| x10 k =