SITUATION 4- Hydrographic Survey- End Area Hethod The area bounded by the water line of a reservoir and the contours with a contour interval of 2 meters are as follows: A1-10250 sq.m. A2-8350 sq.m. A3-7750 sq.m. A4=6900 sq.m. A5-5250 sq.m. Compute the volume of reservoir using the end area method,

SITUATION 4- Hydrographic Survey- End Area Hethod The area bounded by the water line of a reservoir and the contours with a contour interval of 2 meters are as follows: A1-10250 sq.m. A2-8350 sq.m. A3-7750 sq.m. A4=6900 sq.m. A5-5250 sq.m. Compute the volume of reservoir using the end area method,

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Volumes

Volume usually is the dimensional quantity that involves the evaluation of any three-dimensional figure enfolded inside a closed space. The SI unit (International System of Units) of volume is m3 and the dimensional unit of volume is [L3]. For estimation of the volume of any figure, various formulae are used. Another application of volume includes the reference in the sound levels, the higher the sound intensity, the louder the sound heard, and hence, the larger the volume. The SI unit of sound volume is decibels (dB).

Question

SITUATION 4- Hydrographic Survey- End Area Hethod
The area bounded by the water line of a reservoir and the contours with a contour interval of 2 meters are
as follows:
A1-10250 sq.m.
A2-8350 sq.m.
A3-7750 sq.m.
A4=6900 sq.m.
A5-5250 sq.m.
Compute the volume of reservoir using the end area method.

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3. The boundary of the water surface of a reservoir is shown by irregular outline KLMNOPQR. Soundings were taken on parallel ranges QK, PL, and OM for the purpose of determining the volume of water in the reservoir. The horizontal distances (m) which were measured for locating the ranges and the soundings, and also the depth (m) which were measured where soundings were taken are shown. Calculate the following: a. Areas (sq.m.) of the cross-sections of ranges QK, PL, and OM. Assume that the cross-sectional areas of ranges R and N are negligible or nearly zero. b. Volume (cu.m.) of water between ranges. c. Total volume (cu.m.) of water contained in the reservoir. R 5.275 Q 2658 t612 -5.591- -7.874- -4.754- 2.150 6.496 -6.725 -3.052- -7.151- -6.499- -5.498- 2,55N 1.076 2.077 3.754 2.636 3.428 8.390 -5.251- +3.676 -5.994 -5.497- -6.031- !! 0.873 0.902 1.714 M 2.702 9. 106 N
kindly asnwer
SHOW EGL WITH ELEVATIONS AND HEADLOSSES.
In determining the volume of water impounded in a reservoir by the contour-area method, a planimeter is used on a map of scale (1/2,400 ). areas in square inches on the map between the lower contour line 1 and the higher contour line 4 were determined in the table below Contour interval on the map is: 9 ft. Compute the reservoir water volume in the unit (Acre-foot). Round your answer to 2 decimals. Area Contour Square inch area (Acre) Volume (Acre-ft) Contour line 1 (Low) 4 Contour line 2 contour line 4 8. Contour line 4 (High) 10
*refer from the illustration attached* determine: (a) Resolve the attached problem if the vertical distance between contour levels is 2.0m. Which has a larger value of volume? Make a conclusion of your answer. ***COMPLETE SOLUTION; 3 decimal places all answer; with Diagram.
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Use only Direct Integration Method 2. AF K M 2 B kN/m 60 mm * MM त्र d 3 EI= 5x10² KN m² Sc 0₂= 1)