Simplify the following Boolean function in product-of-sums form by means of a four-variable map. Draw the logic diagram with (a) OR-AND gates; (b) NOR gates. Implement on CircuitVerse. F(w, x, y, z) = ∑( 0, 2, 4, 5, 6, 7, 8, 10, 13, 15)

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A: for solving using kmap, draw the map and then put the literal in it and further solve it.

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A: Canonical PoS form means Canonical Product of Sums form. In this form, each sum term contains all…

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A: Rules used here is  a+a=a A+1=1

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Q: 1. Given a Boolean function f : {0,1}" → {0, 1} and a boolean circuit C of size |C| = s that…

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Q: Question 5: F(a,b,c,d)=[(0,1,3,6,10,11,14) Implement the above boolean function using a. 4:1 MUX(s)…

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Q: 2- Implement the following function with only AND and NOT gates. F=A B + ĀB+B C W=XY (X Z + X YZ + Y…

A: here, I have to provide solution for the above question.

Q: Discussion 1. Explain the case when we subtract 1 from 0

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Q: Then reconstruct the circuit above using

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Q: Simplify the following Boolean function using Karnaugh map. F(A, B. C. D)…

A: Solution  a F(A,B,C,D)=  Σm (0 ,1 ,2, 3, 4 ,5 ,6 ,7,8 ,9, 10 ,13, 15)

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Q: A+B°C + (A (B +C')

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Q: For Q(a,b,c)= ∏[product of]M(0,2,4,6) what is the reduced form of the logic function in POS form?

A: Reducing the expression using K-Map:

Q: 2. FA,B,C,D) - Σ (0,6, 8 , 13, 14) d(A,B,C,D) - Σ (2, 4, 10) %3D

A: C'D' C'D CD CD' A'B' 1     X A'B X     1 AB   1   1 AB' 1     X

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