Simplify the following Boolean expressions to a minimum number of literals: ( a + b + c ′ ) ( a ′ b ′ + c )

Simplification of the Boolean expression A(AB’)’ + A’ + B’  yields which of the following results? B 0 A 1

Simplify the following Boolean expression uing Boolean algebra B(A'C'+D')'+AC+ABC'+B'

Draw logic diagram for the following expression F = ( AB + CD) C '

Simplify the following boolean expression C+B'C'

---SIMPLIFICATION VIA BOOLEAN ALGEBRA--- 1.) Use boolean algebra to simplify the equation. SHOW YOUR WORK, one step per line. You should use only variable names, negation (with ``), AND (by putting terms next to each other), OR (with `+`), and parentheses. In addition, each line should start with an equal sign (`=`). The first step has been done for you to show how. As a hint, problem 1c requires De Morgan's Law. Example) f(Z,Y,X) = (!Z+Z)Y!X + !YX = Y!X + !YX = !ZY!X + ZY!X + !YX la) f(A,B,C) = !A!BC + A!B!C + !ABC + !AB!C + A!BC

4. Convert the following expressions into sum-of-products and product-of-sums forms: (a) (XY+Z) (Y+XZ) (b) (A+B)(B+C) (c) WXY+WXZ+WXZ+YZ

1. Simplify the following Boolean expressions to a minimumnumber of literals: a. xy + xy ′ b. ( x + y ) ( x + y ′ ) c. xyz + x ′ y + xyz ′ d. ( x + y ) ′ ( x ′ + y ′ ) ′