Show that for & -distribution with n'dif.,about meath 13 given by:√n r[(1-1)/2] / √55/4/2mean deviation

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that the lifetimes of TV gives are normally distributed with a standard deviation of 1.2 years. Suppose also that exactly 30% of the tubes die before 5 years. Find the mean lifetime of tv tubes. Carry your intermediate computations to at least 4 decimal places. Round your answer to at least one
4.1 Suppose X ~ N(15, 6). What value of x is 1.5 standard deviations to the left of the mean? Round to one decimal place
A variable xx is normally distributed with mean 21 and standard deviation 3.Round your answers to the nearest hundredth as needed.a) Determine the zz-score for x=26x=26. z=z= b) Determine the zz-score for x=15x=15. z=z= c) What value of xx has a zz-score of 2.332.33? x=x= d) What value of xx has a zz-score of −1.3-1.3? x=x= e) What value of xx has a zz-score of 00?
arn.squ.edu.om/mod/quiz/attempt.php?attempt=1766808&cmid=8751228&page=D21 SYSTEM (ACADEMIC) s Statistics 1 || Spring21 Time left 0: Suppose a company produces lightbulbs with a mean lifetime of 1000 hours and a standard deviation of 50 hours. So, the z-score for a particular lightbulb that lasts for only 700 hours is a. 300 b. 6
3.- It has been found that the waiting time to obtain a table in a cafe during rush hour has a normal distribution with a mean of 130.7 min. and a standard deviation of 12.5 min. How long do people have to wait to be given a table with the following probability?a) P (X ≥ Xo) = 0.83.b) P (X ≥ Xo) = 0.12c) P (X ≤ Xo) = 0.92d) P (X ≤ Xo) = 0.07
Suppose that X has a Weibull distribution with ß = 0.3 and 5 = 100 hours. Determine the following. Round the answers to 3 decimal places. (a) P (X 5000) = i
Assume x is normally distributed with a mean of 2 and a standard deviation of 2. Find: a.P(X=2) b.P(X<2) c.P(X>=2) d.P(2 < X < 4)
7. If you made only n = 1 measurement of rack height, the standard deviation of 41 measurement would be (a) zero, because there is no difference between the value and the average. (b) Equal to the measured value. (c) Undetermined, because you need more measurements to find a standard deviation (d) Infinite because the denominator (n – 1) is zero.
Solve this problem to find standard deviation to the nearest 10th
I am confused. I do not understand how they got 0.0681 when using the standard normal Z table for 1.49. According to my table, that is for -1.49, and positive 1.49 has a z-score of 0.9319. Using the normalcdf function on my calculator, I can only get that result if I set 1.49 as my lower bounds and 10^99 as my upper bounds. Is this question asking for a right or left area? I thought the area to the left was supposed to be negative.
A variable xx is normally distributed with mean 20 and standard deviation 3.Round your answers to the nearest hundredth as needed.a) Determine the zz-score for x=22x=22. z=z= b) Determine the zz-score for x=18x=18. z=z= c) What value of xx has a zz-score of 1.331.33? x=x= d) What value of xx has a zz-score of −0.3-0.3? x=x= e) What value of xx has a zz-score of 00? x=x=

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Show that for +-distribution with n'dof., about meath 13 given by: √n [[(1-1)/2] / √5564/2 mean deviation