show how for molecule C11H1402 the following fragments may be obtained given the mass spec highest peak was 121 followed by 136, 91, 43 with the parent peak being 178 (the molecular weight) H3C اف P CH3 CH3
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- Following is the mass spectrum of bromocyclopentane. The molecular ion m/z 148 is of such low intensity that it does not appear in this spectrum. Assign structural formulas for the cations of m/z 69 and 41.Following is the mass spectrum of an unknown compound. The two highest peaks are at m/z 120 and 122. Suggest a structure for this compound. (Data from http://webbook.nist.gov/chemistry/.)Following is the mass spectrum of 3-methyl-2-butanol. The molecular ion m/z 88 does not appear in this spectrum. Propose structural formulas for the cations of m/z 45, 43, and 41.
- How will E for an isolated 13C nucleus compare with that of a 1H nucleus?In a 300 MHz NMR spectrometer, A) what is the Larmor frequency in MHz of a 15N nucleus? g H = N 26.752; g = 2.7126; B) Using the same NMR instrument, suppose that a 13C nucleus from a sample generates a signal which has a frequency of 11,250 Hz higher than that from the carbons in TMS. What is the chemical shift of that carbon atom from the sample? A) 30 MHz; B) 0.15 ppm OA) 25 MHz; B) 0.35 ppm A) 35 MHz; B) 0.30 ppm OA) 25 MHz; B) 0.55 ppmshow how for molecule C11H1402 the following fragments may be obtained given the mass spec highest peak was 121 followed by 136, 91, 43 with the parent peak being 178 (the molecular weight) CH3 H3C CH3
- 9 What compound has a formula of C5H120 * ?and a peak at 3300 cm-1 (ähäi 1) Ether Alcohol Aldehyde KetoneMass spectroscopic. What is the isotopic peak pattern of each : Organic compound with 2 bromine atoms. Organic compound with 2 chlorine atoms.Q.1. Predict the relative intensity of the M, M+1, and M+2 peaks for a low resolution mass spectrum of a compound with molecular formula, C6H13Br. The natural abundances of the select isotopes are given below. 35 Cl: 75.8% 79Br: 50.5% 12C: 98.89% 37Cl: 24.2% (The ratio is almost 3:1) 81Br: 49.5% (The ratio is almost 1:1) 13C: 1.11%
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