Show how example code of how to find the repeated lines of code within a file using loops. No functions can be used to complete this.

Debug the following phython code. """This function reads in data from the file specified by filename. This data is read line by line and unpacked into a single variable called data. argumentsfilename - the name of the file to be read returnsdata - a list of data, each element is a list that corresponds to the set of entries separated by commas in the original file. To access the first entry use data[0]. If x = data[0], then x[0], through x[3] will correspond to entries in the file that are read in. """ def read_file(filename):fin = open(filename,'r')line = fin.readline()data = []while line:data.append(parse_line(line))line = fin.readline()return data

pls  code in pythonplagiarism: This Boolean function takes two filenames. If any line occurs in both files, return True.If not, return False. I suggest using nested loops. With nested loops, we call the loop that is in thebody of the other loop, the "inner loop". The loop that contains the inner loop is the "outer loop". Openthe second file inside the outer loop:for line1 in file1:file2 = open(fname2)for line2 in file2:Python only lets you read the file once per open, so you need this order of instructions. Make sure yourreturn False is outside of both loops. Otherwise, you will only compare the first two lines of thefiles. Make sure you close the file that gets read repeatedly after the inner loop but still inside the outerloop.Here is some (more complete) pseudocode to get you started:open file 1for line1 in file 1open file 2for line2 in file 2:if line1 == line2:return Trueclose file 2return False

I need help on my python assignment.