Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Show all the steps to find value of CRC for dataword 10110101 and the divisor (polynomial value) is 10011.
What is the value of CRC?
What is binary value of Codeword that will be sent on the network
Show all the steps to determine if there is any error in the received code word: 101101010100 where the divisor is 10011
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- If the sequence number space is k-bit, use Go-Back-N and selective-repeat. How big may the sender window be?arrow_forwardFor example: Binary value of character ‘B’ from ASCII table is 01000010Dataword is 1000010 Even Parity Bit is 0 Codeword: 10000100 Even Parity – Complete the following table using Even Parity Character Binary Datawordfrom ASCII table(7-bit value) Parity BitValue TransmittedCodeword ReceivedCodewordat Receiver Check ifthecodewordisrejected t 1010100 10101101 h 1101000 11010000 i 1101001 11010010 s 1110011 11100110arrow_forwardDecode the message without encoding techniques.(I need an explanation on how it's done. Having diffulties. Thanks) 01001110 01100101 01110110 01100101 01110010 00100000 01100111 01101111 01101110 01101110 01100001 00100000 01100111 01101001 01110110 01100101 00100000 01111001 01101111 01110101 00100000 01110101 01110000 00001010 01001110 01100101 01110110 01100101 01110010 00100000 01100111 01101111 01101110 01101110 01100001 00100000 01101100 01100101 01110100 00100000 01111001 01101111 01110101 00100000 01100100 01101111 01110111 01101110 00001010 01001110 01100101 01110110 01100101 01110010 00100000 01100111 01101111 01101110 01101110 01100001 00100000 01110010 01110101 01101110 00100000 01100001 01110010 01101111 01110101 01101110 01100100 00100000 01100001 01101110 01100100 00100000 01100100 01100101 01110011 01100101 01110010 01110100 00100000 01111001 01101111 01110101 00001010 01001110 01100101 01110110 01100101 01110010 00100000 01100111 01101111 01101110 01101110 01100001…arrow_forward
- If the sequence number space has k bits, use the Go-Back-N and selective-repeat strategies. What is the maximum sender window size?arrow_forwardHow many 14-bit strings (that is, bit strings of length 14) are there which: a. Start with the sub-string 011? 2048 b. Have weight 4 (i.e., contain exactly 4 1's) and start with the sub-string 011? 330 c. Either start with 011 or end with 01 (or both)? 6144 d. Have weight 4 and either start with 011 or end with 01 (or both)? 825arrow_forwardHow many bit strings contain exactly five 0’s and ten 1’s if every 0 must be immediately followed by a 1?arrow_forward
- What would be the acknowledgment number sending by the receiver after it receives 3rd datagram from the senderarrow_forwardIf the sequence number space contains k bits, think about using both the Go-Back-N and selective-repeat techniques. What is the largest sender window that is permitted?arrow_forwardConsider a binary code that consists of only four valid code wards as given below: 00000, 01011, 10101, 11110 Let the minimum Hamming distance of the code be p and the maximum number of erroneous bits that can be corrected by the code be q. Then the values of p and q arearrow_forward
- When the result of an unsigned arithmetic operation is too big to fit into the destination, what flag is set?arrow_forwardI need some help with this questionarrow_forwardDraw a FSA which accepts all binary strings which start with 0, the length of the string is even but the number of 1's in the string is odd. 0111, 01 and 000111 should be accepted while 111 and 0011 should notarrow_forward
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