Sequential search algorithm has running time in terms of n O(n) O(nk) O(n*Ig(n)) O(n^2) O(n^2*lg(n)) O(n^3) other
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- Sequential search algorithm has running time in terms of n O(n) O(nk) O(n*lg(n)) O(n^2) O(n^2*lg(n)) O(n^3) other Binary search algorithm has running time in terms of n O(n) O(Ig(n)) O(n*lg(n)) O(n^2) O(n^2*lg(n)) O(n^3) otherMergeSort algorithm has running time in terms of n O(n) O(lg(n)) O(n*lg(n)) O(n^2) O(n^2*lg(n)) O(n^3) otherThe number of operations executed by algorithms A is 5n^2 and by algorithm B is 30n^3. Determine n0 such that B is better than A for all n > n0.
- Show that n!=O(n^n)Algorithm to illustrates the procedure for Fibonacci search. Here n, the number of data elements is such that:i) Fk+1 > (n+1); andii) Fk + m = (n +1) for some m ≥ 0, where Fk+1 and Fk are two consecutive Fibonacci numbers.The big-O time efficiency for performing Binary search for an item in a sorted list is: O(1) O(log(n)) O(n) O(nlog(n))
- Consider the following algorithm that uses a sorted list of n elements (alist). What is the worst case runtime of this algorithm? for each element in alist 1. ask the user for an input, call it value 2. search value in alist using binary search 3. if value exists in alist, print "successful" otherwise print "unsuccessful" Question options: a. O(log n) b. O(n) c. O(n log n) d. O(2^n) e. O(n^2) f. O(1)Create an algorithm that demonstrates the Fibonacci search procedure. The number of data elements n is chosen in such a way that: I Fk+1 > (n+1); and ii) Fk + m = (n +1) for some m 0, where Fk+1 and Fk are two consecutive Fibonacci numbers.Consider the following algorithm that uses a sorted list of n elements (alist). What is the worst case runtime of this algorithm? for each element in alist 1. ask the user for an input, call it value 2. search value in alist using the binary search algorithm 3. if value exists in alist, print "successful" otherwise print "unsuccessful" Question 10 options: O(2^n) O(n log n) O(log n) O(n^2) O(n) O(1)
- Using the substitution method, prove that: T(n) = T(n − 1) + 4n is O(n^2)The time to merge two sorted lists of size n is_ ㅇ(1) O(n) ㅇ(nlogn) o(logn) o(n*n)Write Algorithm procedure code to illustrates the procedure for Fibonacci search. Here n, the number of data elements is such that:i) Fk+1 > (n+1); andii) Fk + m = (n +1) for some m ≥ 0, where Fk+1 and Fk are two consecutiveFibonacci numbers.