Select the scenario below that you would expect to reach diffusion equilibrium first. Each dye is added to a beaker of water (Red dye 40 has a molecular mass of 496.42 g / mole; blue dye 1 has a molecular mass of 799.9 g/mole) Red dye 40 at room temperature (20 C) Blue dye 1 at room temperature (20 \deg C) Red dye 40 at 40 Blue dye 1 at 40 \ deg C

Primary reaction product

500.0 mL of 0.100 mol·L HCl(aq) was added to a high quality insulated calorimeter containing 500.0 mL of 0.100 mol·LNaOH(aq). Both solutions had a density of 1.000 g·mL and a specific heat of 4.184 J·g ·K . The calorimeter had a heatcapacity of 850.0 J·K . The temperature of the entire system rose from 25.50 C to 26.05 C.Calculate the heat of reaction.   Thank you!

Name these organic compounds: Η Η Η Η Η Η ||| C=C=C-H ||| Η Η Η Η Η II H — C =C=C=C=C - H ||||| Η structure Η Η Η Η Η Η H H Η Η Η | Η ||| H – C – C =C=C=C=C=CH ||||||| Η Η Η Η Η Η Η name Π Π Π

Order these chemical species by increasing pH of an 0.1 M aqueous solution of each. That is, imagine making an 0.1 M solution of each species. Select1 next to the species that makes the solution with the lowest pH. Select 2 next to the species that makes the solution with the next higher pH, and so on. Notice that some of the rankings have been filled in for you already. Also notice that water is on the list. For that particular case, just compare the pH of pure water to the pH of the other solutions. Note for advanced students: for all charged species, you may assume the necessary counterions act as neither acids nor bases. relative pH of 0.1 M aqueous solution species H20 4 H,PO4 HNO, (Choose one) NO2 7 OH (Choose one) HF (Choose one) ▼

Give the expression for the Ksp for the following CACO3(s) Ca*2 CO3 2 Ksp = %3D

Q1. Consider the following reaction: 2 KMnO4(aq) + 3 H₂SO4(aq) + 5 H₂O2(aq) Complete the table below (answers must be values with proper signs and units). A[H₂SO4)/At -0.156 mol L ¹5-1 ->> Δ[02]/ΔΙ 0.260 mol L¹ s1 K₂SO4(aq) + 2 MnSO4(aq) + 8 H₂O(1) + 5 02(aq) A[KMnO4]/At Reaction Rate -0.104 mal L'5" 0.052 MOLL'S!

-1/3=j/4-10/3 What is j?

I need an answer for this question. Thank you. #1