The enthalpy changes, AH, for three reactions are given. H, (g) + 0,®) – H,0) AH = -286 kJ/mol Са2+ (aq) + Н,(g) Са?* (aq) + H,О0) Ca(s) + 2 H+(aq) AH = -544 kJ/mol СаO(s) + 2 H*(аq) AH = -193 kJ/mol Using Hess's law, calculate the heat of formation for CaO(s) using the reaction shown. Ca(s) + СаO() AH = kJ/mol

You wish to find the enthalpy for the reaction 6 Gel (s) + 14 NH:1 (s) → 3 Ge:H6 (1) + 7 N2 (g) + 38 HI (g) kJ/mol Given the following equations Equation 1: 2 Ge (s) + 3 H2 (g) → Ge:H6 (1) AH = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) – Gel: (s) + 2 H2(g) AH = -247.8 kJ/mol Equation 3: 2 NH&| (s) → N2 (g) + 2 HI (g) + 3 H2(g) AH = 455.8 kJ/mol 2 4 C What would be the enthalpy change, in kJ/mol, for 6 Gel4 (s) + 12 H2(g) - 6 Ge (s) + 24 HI (g)? 7 8 9. +/- x 100 3. 1,

The standard heat of formation, AH, is defined as the enthalpy change for the formation of one mole of substance from its constituent elements in their standard states. Thus, elements in their standard states have AH = 0. Heat of formation values can be used to calculate the enthalpy change of any reaction. Part A For which of the following reactions is AH equal to AH of the product(s)?You do not need to look up any values to answer this question !3! Check all that apply. Consider, for example, the reaction > View Available Hint(s) 2NO(g) + O2(g) = 2NO2(g) with heat of formation values given by the following table: O 2Na(s) + Ch (x)-2NACI(s) O H,O, (g)→02(g) + H,O(g) AH (kJ/mol) Substance NO(g) - Na(s) +C½(1)¬NACI(s) 90.2 O2(g) O 2H,(g) + O2(g)--2H,O(g) NO2 (g) 33.2 O H2(g) + 0,(g)→H,O(g) Then the standard heat of reaction for the overall reaction is o Na(s) +Cl, (g)¬NACI(s) AH= AH; (products)- AH (reactants) 2(33.2) 12(90.2) + 0) Submit Previous Answers Request Answer 114 kJ P Pearson…

Given the following standard enthalpy change, use the standard enthalpies of formation in slide 51(Table 5.3 in chapter 5) to calculate the standard enthalpy of formation of CuO(s): CuO(s) + H2 (g) → Cu(s) + H20 (I) AH° = -129.7 kJ Use the editor to format your answer

I am confused on how to find the enthalpy change with this information. Thank you!

Please answer both questions

Consider these reactions, where M represents a generic metal. 1. 2 M(s) + 6 HCI(aq) 2 MCI, (аq) + 3 Н, (2) AH1 = -556.0 kJ 2. HCl(g) HCl(aq) AĦ2 = -74.8 kJ 3. H, (g) + Cl, (g) → 2 HCI(g) ΔΗ = -1845.0 kJ 4. MCI, (s) – MCI, (aq) AĦ4 = -493.0 kJ Use the given information to determine the enthalpy of the reaction 2 M(s) + 3 Cl, (g) – - 2 MCl, (s) -556.0 ΔΗ- Incorrect

A chemist measures the enthalpy change AH during the following reaction: Fe(s) + 2 HCl(g)→FECL,(s) + H,(9) AH=-157, kJ Use this information to complete the table below. Round each of your answers to the nearest kJ/mol. reaction ΔΗ x10 을Fels) + 3 1 1 1 -HCI(g) FeCl, (s) + 3 (8) | kJ 3 FeCl, (6) + (8) Fe(s) + HCI(g) 6 3 FeCl, (s) + H, (g) Fe(s) + 2HC1(g)

If a system has 225 kcal of work done to it, and releases 5.00 x 10² kJ of heat into its surroundings, what is the change in internal energy (AE or AU) of the system? ΔΕ= kJ

A chemist measures the enthalpy change AH during the following reaction: Sg(s) + 24 F,(g)→8 SF(g) AH=-9672. kJ Use this information to complete the table below. Round each of your answers to the nearest kJ/mol. reaction ΔΗ 10 SSF, (3) → S, (3) + 24F, (z) S,6) + 6F, (g) 2SF, (3) 4 4 SF, (e) -- S,(1) + 4F, (3)