Segmentation: Select all of the following statements that are true. In segmentation, a logical address always has a length of 32 bit. In order to translate logical into physical addresses, the memory management unit uses the segment part of the logical address to determine the start address in the segment table and adds the offset to this to get the physical address. In segmentation, the logical address consists of a segment part and an offset. The segment length is limited by the maximum possible segment number. When applying segmentation, processes are only allowed to access the memory within their segments. Segments can be assigned access rights and privilege levels.

When a memory location is used as a pointer, what area of memory does the pointer's address value come from? static data stack heap / free store

5- Create an algorithm in assembly that will compute the area of a triangle. Here is the state of the memory when starting the algorithm: Base is stored as an 8 bit unsigned integer in a memory location pointed to by the special register X. Height of the triangle is stored as an 8 bit integer in a memory location pointed to by the special register Y. Your computed area of the triangle should be stored in memory at a location pointed to by the special register Z. If multiple rows of memory are required, then Z indicates the starting address. Requirements Clearly list the assembly commands required for this algorithm. How many rows of program memory are required for this algorithm? How many clock cycles (according to the AVR ISA) are required for this algorithm? What addressing mode is used for each assembly instruction?

What does "address space" in a memory block really mean?

Computer organization and assembly language Please help me with this. I have to write line by line what each line of codes does. CODE IS BELOW: .model small  .386  .stack 100h    .data  msg1 db 13, 10, "Enter any number --> ", "$" msg2 db  "Enter an operation +,- * or /  --> ",13, 10, "$" msg3 db  "The Operation is --> ", "$" msg4 db  "The result is --> ", "$" By_base dd 21 by_10 dd 10  ; 32 bits variable with initial value = 10 sp_counter db 0 ; 8 bits variable with initial value of zero disp_number dd 0 ; 32 bits variable with initial value = 0 disp_number2 dd 0 disp_number3 dd 0 op_type db 0 last_key dd 0 ; 32 bits variable with initial value of zero remainder db 0 .code    main proc mov ax,@data;set up datasegment movds,ax         mov dx,offset msg1 call display_message   callm_keyin   calloperation mov dx,offset msg1 calldisplay_message   callm_keyin cmpop_type, "+" jnz short skip_plus   callop_plus   skiP_plus: cmp op_type, "-" jnz short skip_minus callop_minus…

Microprocessor8086 Write the assembly of Write on the data segment and create number1 and number2 variables in byte size and initialize the variables Then compute the sum ,subtraction,multiplication and division of the defined variables and load the values to the variables which you create on the data segment Perform the operations below in sequence with defined on the data segment numbers in array Find the sum of array and average of array Find the maximum and minimum numbers of array If it’s possible on emu8086 app