Sections 12.6 2) What is the pH of 0.0020 M HCI? How does the pH of 0.0020OM HF compare? PH = -"log [n"] PH = -log L.0020]- 2.7 They will be the same. Sections 12.7 3) Write the balanced molecular equation for neutralization reactions that take place when the following water solutions are mixed. a) HCI (aq) + Lici Cag) LIOH (aq) 2-H - 2 1- CI - 1 (- Li - 3. b) Cd(OH)2 (aq) HI (aq) Cd I ft + OH2H c) A 125.00mL sample of an HI solution is titrated to the equivalence point using 0.209 M Cd(OH)2. If the titration requires 79.55mL of Cd(OH)2, what is the concentration (molarity) of HI?

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MILK IS ACIDIC.
Sections 12.6
2) What is the pH of 0.0020 M HCI? How does the pH of 0.0020M HF compare?
PH--1og
L.0020]
=2.7
They will be the same.
Sections 12.7
3) Write the balanced molecular equation for neutralization reactions that take place when the following water
solutions are mixed.
a)
HCl (aq)
LIOH (aq)
2-H - 2
|- CI - I
- Li - 1
1-0 -1
+ LicI Caq)
b) Cd(OH)2 (aq)
HI (aq)
Cd I fo # OH2H
c) A 125.00mL sample of an HI solution is titrated to the equivalence point using 0.209 M Cd(OH)2. If the
titration requires 79.55mL of Cd(OH)2, what is the concentration (molarity) of HI?
71.55ML >
Concentra tion Cd COH)2=.209M
Vof Cd (ot),= 79.55ML
HI = ZM
Moles of HI is titrated = ZM X.125.00ML
= ,0 7955 L
.07955 L.209M=.0166Mol
cd (OH)2 + HI ) Cd I
+ H30
1:1
Transcribed Image Text:MILK IS ACIDIC. Sections 12.6 2) What is the pH of 0.0020 M HCI? How does the pH of 0.0020M HF compare? PH--1og L.0020] =2.7 They will be the same. Sections 12.7 3) Write the balanced molecular equation for neutralization reactions that take place when the following water solutions are mixed. a) HCl (aq) LIOH (aq) 2-H - 2 |- CI - I - Li - 1 1-0 -1 + LicI Caq) b) Cd(OH)2 (aq) HI (aq) Cd I fo # OH2H c) A 125.00mL sample of an HI solution is titrated to the equivalence point using 0.209 M Cd(OH)2. If the titration requires 79.55mL of Cd(OH)2, what is the concentration (molarity) of HI? 71.55ML > Concentra tion Cd COH)2=.209M Vof Cd (ot),= 79.55ML HI = ZM Moles of HI is titrated = ZM X.125.00ML = ,0 7955 L .07955 L.209M=.0166Mol cd (OH)2 + HI ) Cd I + H30 1:1
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