Sec (30) (08300 8. You lean a 20 foot ladder is leaning against a wall so you can replace a burned out light at the top of the wall. You push the bottom of the ladder toward the wall at a rate of 1 foot per second to raise the top of the ladder along the wall toward the light. When the base of the ladder is 12 ft from the wall, how fast is the top of the ladder moving up the wall? √x² + y² = 1² Ⓒ 2x / 42 + 2y o/x = 1² ot dy 2x = x + 2y = 1 = 0 ot de df 2+ = 147/5 dt Page 4 of 7 20ft, 12 ft

A ladder is leaning against a wall. The ladder is 17 feet long. The top of ladder slides down the wall at a rate of 3 feet per second. How fast is the bottom of the ladder sliding away from the wall when the top of the ladder is touching the wall 8 feet above the ground. 5/8 -5/8 -5/4 4/5 8/5

3/2=(w+2)/5 Solve for w.

An oil rig breaks and begins to leak oil into the arctic ocean at an increasing rate of R(t) = 30t + 10 litres per day. At the instant of breakage (t=0), 10 litres of oil was spilled into the ocean via the emergency release valve. What is the equation V(t), the amount of oil (in litres) leaked into the ocean at time t days? V(t) = 5² + 20t + 100 V(t) = 10²2 + 5/₂t + 1000 V(t) = 5/2² +10t + 100 Vt) = 15²2² +10t + 1000 Vt) = 5t² + 10t + 1000 Vt) = 15² + 10t+ 10 OMA =152 +5/2t + 1000 Иt) = 10²² + 20t + 100