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An oil rig breaks and begins to leak oil into the arctic ocean at an increasing rate of R(t) = 30t + 10 litres per day. At the instant of breakage (t=0), 10 litres of oil was spilled into the ocean via the emergency release valve. What is the equation Vt), the amount of oil (in litres) leaked into the ocean at time t days? V(t) = 5² + 20t + 100 V(t) = 10²2 + 5/₂t + 1000 V(t) = 5/2² +10t + 100 Vt) = 15²2² +10t + 1000 Vt) = 5t² + 10t + 1000 V(t) = 15²2² + 10t + 10 1A)=15+² +5/-t -

An oil rig breaks and begins to leak oil into the arctic ocean at an increasing rate of R(t) = 30t + 10 litres per day. At the instant of breakage (t=0), 10 litres of oil was spilled into the ocean via the emergency release valve. What is the equation Vt), the amount of oil (in litres) leaked into the ocean at time t days? V(t) = 5² + 20t + 100 V(t) = 10²2 + 5/₂t + 1000 V(t) = 5/2² +10t + 100 Vt) = 15²2² +10t + 1000 Vt) = 5t² + 10t + 1000 V(t) = 15²2² + 10t + 10 1A)=15+² +5/-t -

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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An oil rig breaks and begins to leak oil into the arctic ocean at an increasing rate of R(t) = 30t + 10 litres per day. At the instant of breakage (t=0), 10 litres of oil was spilled into the ocean via the emergency release valve. What is the equation V(t), the amount of oil (in litres) leaked into the ocean at time t days? V(t) = 5² + 20t + 100 V(t) = 10²2 + 5/₂t + 1000 V(t) = 5/2² +10t + 100 Vt) = 15²2² +10t + 1000 Vt) = 5t² + 10t + 1000 Vt) = 15² + 10t+ 10 OMA =152 +5/2t + 1000 Иt) = 10²² + 20t + 100
Transcribed Image Text:An oil rig breaks and begins to leak oil into the arctic ocean at an increasing rate of R(t) = 30t + 10 litres per day. At the instant of breakage (t=0), 10 litres of oil was spilled into the ocean via the emergency release valve. What is the equation V(t), the amount of oil (in litres) leaked into the ocean at time t days? V(t) = 5² + 20t + 100 V(t) = 10²2 + 5/₂t + 1000 V(t) = 5/2² +10t + 100 Vt) = 15²2² +10t + 1000 Vt) = 5t² + 10t + 1000 Vt) = 15² + 10t+ 10 OMA =152 +5/2t + 1000 Иt) = 10²² + 20t + 100
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