A First Course in Probability (10th Edition)
10th Edition
ISBN: 9780134753119
Author: Sheldon Ross
Publisher: PEARSON
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- The accompanying table contains data on the weight, in grams, of a sample of 50 tea bags produced during an eight-hour shift. Complete parts (a) through (d). Click the icon to view the data table. (Round to two decimal places as needed.) Find the p-value. p-value = .819 (F State the conclusi Do not reject H b. Construct a 90 The 90% confider (Round to four de Interpret the 90% More Info Tea Bag Weight (in grams) 5.65 5.45 5.42 5.41 5.53 5.34 5.54 5.46 5.53 5.59 5.42 5.51 5.55 5.54 5.61 5.56 5.47 5.44 5.49 5.39 5.46 5.63 5.53 5.32 5.68 5.29 5.49 5.76 5.56 5.41 5.57 5.59 5.52 5.33 5.49 5.54 5.61 5.44 5.45 5.24 5.56 5.63 5.49 5.58 5.68 5.43 5.49 5.57 5.58 5.35 I Xarrow_forwardAmong freshmen at a certain university, scores on the Math SAT followed the normal curve, with an average of 550 and an SD of 100. The SAT score of a student whose score is at the 99th percentile is closest to what value? Group of answer choices 780 400 760 805arrow_forwardA survey was conducted two years ago asking college students their top motivations for using a credit card. You think this distribution has changed. You randomly select 425 college students and ask each one what the top motivation is for using a credit card. Can you conclude that there has been a change in the distribution? Use a = 0.025. Complete parts (a) through (d). Response Old Survey % 29% New Survey Frequency, f Rewards 110 Low rates Cash back Discounts 23% 96 21% 109 7% 46 Other 20% 64 O B. The distribution of motivations is 110 rewards, 96 low rate, 109 cash back, 46 discounts, and 64 other. O C. The distribution of motivations is 29% rewards, 23% low rate, 21% cash back, 7% discounts, and 20% other. Which hypothesis is the claim? o Ho (b) Determine the critical value, Yo, and the rejection region. X = 11.143 (Round to three decimal places as needed.) Choose the correct rejection region below. Oc. Xarrow_forwardA distribution of values is normal with a mean of 120 and a standard deviation of 4.Find the interval containing the middle-most 68% of scores: Enter your answer using interval notation. Example: (2.1,5.6)arrow_forwardThe mean heignt Of male College Studen ts ina large city is 68 Inches and the Stander d deviotion IS 5 Inches. What heignt Would a male College Student must have lo order for the Students heignt to be the cutoff point for the 9sth percent1le ? (what is tne lowest heagnt n the top 5 %?)arrow_forwardSave Suppose a random sample of n = 390 teenagers 13 to 17 years of age was asked if they use social media. Of those surveyed, 276 stated that they do use social media. Find the sample proportion of teenagers 13 to 17 years of age who use social media. The sample proportion is p= (Round to three decimal places as needed.)arrow_forwardIf a person’s z-score equalas 2.08, what is their percentile? Thank you.arrow_forwardalo Smart phone: Among 248 cell phone owners aged 18-24 surveyed, 104 said their phone was an Android phone. Part: 0 / 3 Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is Part: 1/3 Part 2 of 3 (b) Construct a 99.5% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answers to at least three decimal places. A 99.5% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone isarrow_forwardSuppose you are told your BMI is 32, the 70th percentile for your age and sex. Please interpret this percentile age: 28 Femalearrow_forwardWhat percentage of scores fall between the mean and a z score of 1.17? Question 6 options: 6.75 percent 13.59 percent 34.13 percent 37.90 percentarrow_forwardUse the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the difference between proportions of men and women who own smartphones. Assume that you want 95% confidence that your error is no more than 0.03.arrow_forwardAssume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_iosRecommended textbooks for you
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A First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON