Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- our sister breeds Labradors, but is unaware of the genetics of coat color, so she has been mixing and matching various breeding pairs, unable to predict the outcomes. She recently bred two black labs, expecting to get only black lab puppies, but instead, the litter included black, brown, and yellow pups. She is confused, but since you know your genetics, you can explain to her what’s going on. What are the genotypes of these two parents, for both of the genes involved? What are the possible genotypes of the various offspring? (Organize them by phenotype.) Litters of puppies are too small for reliable statistics, but if these two parents had a large number of puppies over time, what are the expected ratios (or fractions or percents) of the three possible coat colors?arrow_forwardHello Heliodors! (cont.) Trait A For Heliodors, having four arm-like extensions is dominant over having two. In a family of Heliodors, Hayden has four arm-like extensions like his mother Helen. His father, Harry, and sister, Holly both have two. What are the genotypes of everyone in this family of Heliodors? What is Helen's genotype? O Not enough information to determine aa (homozygous recessive) Aa (heterozygous) O AA (homozygous dominant)arrow_forwardYou are a zoologist working with Giraffes. Their main traits are: Grey tongues (G+), Rudimentary Horns (R+), Long necks (L+) . You perform the following testcross with an individual with recessive versions of all 3 of the traits. P: G+ R+ L+/G+ R+ L+ x G R L /G R L F1(all identical): G+ R+ L+/G R L What this the distance between G and R? What is the distance between G and L? What is the distance between R and L? What is the correct order of the genes on the chromosome? (5 points) (Hints: You should draw it first. The overall order will not change whether reading from the left or the right side of the chromosome). a. G--R--L b. L--G--R c. G--L--Rarrow_forward
- IN TRANSYLVANIA, SOME PEOPLE EXHIBIT TWO UNUSUAL TRAITS IN WHICH THEY HAVE VERY LONG FRONT TEETH AND THE INABILITY TO BE AWAKE WHEN THE SUN IS UP. BOTH OF THESE TRAITS APPEAR TO BE RECESSIVE. IF A WOMAN WHO IS HETEROZYGOUS FOR TEETH AND HOMOZYGOUS NORMAL FOR BEING IN THE SUN MARRIES A MAN WHO HAS BOTH THESE TRAITS, WHAT COULD BE THE PHENOTYPES AND GENOTYPES OF THEIR CHILDREN? USE A PUNNET SQUARE AND SHOW ALL WORK. LIST THE RATIOS FOR THE GENOTYPES AND PHENOTYPES.arrow_forwardLabrador retrievers are commonly black, brown, or yellow. Two different genes determine coat color in Labrador retrievers. The B gene determines pigment color (B is black, bb is brown). The E gene determines whether the pigment can be deposited in the hair shaft: ee prevents any pigment from being deposited, resulting in yellow dogs. You want to breed Labrador retrievers, and you cross a true-breeding brown Labrador retriever to a true-breeding yellow Labrador retriever. All 15 of the F1 puppies are black. After the puppies grow up, you cross two of the F1 black dogs together. In the F2 generation you get 8 black puppies, 4 yellow puppies, and 3 brown puppies. Part 1 What is/are the possible genotype(s) of the true-breeding brown lab in the P generation? O bbEE Brown bbee O bbEe Could be either answer bbEE or bbEe Part 2 What is/are the possible genotype(s) of the true-breeding yellow lab in the P generation? Obbee Bbee BBee Could be either bbee or Bbee. O Could be either Bbee or BBee.…arrow_forwardPLEASE DO BAR GRAPHS BASED ON DATA: Procedure: Assuming both parents carry three tall genes and three short genes, you will model the inheritance of height for ten different offspring. Flip a coin six times to determine how many tall and short genes the child inherits. Heads represents a tall gene and tails represents a short gene. Record all of your data along with the class data in the tables below Data: Table 1: Group results Flip (Your Group) 1 2 3 4 5 Number of tails 0 1 2 3 4 Number of heads 6 5 4 3 2 Table 1: continued Flip (Your Group) 6 7 8 9 10 Number of tails 5 6 3 2 1 Number of heads 1 0 3 4 5 Table 2: Group and class results Flip Situation 0 T 6 H 1 T 5 H 2 T 4 H 3 T 3 H 4 T 2 H 5 T 1 H 6 T 0 H Your Group Total 1 3 6 10 9 5 1 Class Total 0…arrow_forward
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