
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Transcribed Image Text:IN +3H, ANH,
7
MILE
In both scenarios depicted graphically,
above, the more abundant reactant is
the limiting reactant.
Cite evidence and reasoning to
explain how this is possible.
Clas
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DS
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CL
IS
0
225
The more abundant reactant is the limiting reactant because it doesn't
have enough to fulfill the "recipe." In the first scenario, there needs to be
1N2 and 3H2 to make 2NH3. So even though there are 7 H2, only 6 of
those 7 can be made into 2 2NH3, even though the 1 N2 is already enough
to make an NH3 product. This makes H2 the limiting factor even though
it's the most abundant. In the second scenario, there has to be 1 CH4 and
202 to make the products. With that "recipe," 4 CH4 would need 8 02,
but since there are only 6 02, the amount of product that can be made is
limited even though 02 is technically the most abundant reactant.

Transcribed Image Text:Scenario #1
How many grams of silver chloride (AgCl) are produced from the reaction between
100.0 g of silver nitrate (AgNO,) and 100.0 g barium chloride (BaCl₂) ??
2AgNO3(s) + BaCl₂ (s)
moles
liters
100.0 g
100 g BaCl2 x
100.0 g
Determine the number of moles of product that can be created from 100 g of AgNO₂:
100.0 g-AgNO3 x
1 mole AgNO3
169.87 moles AgNO3
What is the
limiting reactant?
AgNO3
Ba(NO3)2 (5) + 2AgCl (s)
0.5887 moles
1 moles BaCl2
Determine the number of moles of product that can be created from 100 g of BaCl,:
2 moles AgC!
X
1mol Bach
208.23 g BaCl2
X
2 moles AgCl
2 moles AgNO3
0.5887 moles AgCl X 143.2 g AgCl
1 mole AgCl
MOLAR MASSES IF NEEDED:
169.87 g/mol
143,32 g/mol
213.341 g/mol
208.23 g/mol
0.58868 moles
- 200/333.74= 0.5887 moles AgCl
What is the maximum amount of
AgCl that can be formed?
AgNO.
AgCl
Ba(NO₂)₂
200.0/208.23 =
84.37 g AgCl
0.960476 moles AgCl
0.9606 molos
AgCl
0.5887 moles AgCl
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