Scandium (Sc) has the Face-Centered Cubic (FCC) crystal structure. The edge length is a = 0.452 nm. What is the linear density in atoms/nm along direction [110]?

( 100] Problem 4. Calculate a value for the density of FCC platinum in grams per cubic centimeter from its lattice constant a of 0.36263 nm and its atomic mass of 195.09 g/mol. (pts 15)

Draw a sketch of the (111) plane of the FCC unit cell. Are these atoms close packed? Draw a sketch of the close packed plane in hexagonal close packed. It will be simply an atom surrounded by 6 others in the plane.

Answer the following question with drawing the atom configurations of the plane or direction.What is the planar density for the (110) plane in a FCC structure?

Sodium chloride (NaCl) has the rock salt crystal structure and a density of 2.17 g/cm³. The atomic weights of sodium and chlorine are 22.99 g/mol and 35.45 g/mol, respectively. (a) Determine the unit cell edge length. nm (b) Determine the unit cell edge length from the radii in the table below assuming that the Nat and Cl- ions just touch each other along the edges. nm Cation Mg2+ Fe2+ Na+ Ionic Radius (nm) 0.072 0.077 0.102 Anion Ionic Radius (nm) CI- 0²- 0.181 0.140

prove the interplanar spacing of the cubic crystal structure (primitive) [prove the distance in cubic]

Sketch the planar cross section for the following planes in the FCC structure (label the edge lengths in terms of a and R) and calculate the planar densities for the three planes (do so in terms of both atoms/nm2 AND the dimensionless quantity): a. (001)b. (011)c. (111)

2. A 2D representation of crystalline structure is shown below. Please indicate the type of defects in these crystalline materials: (d) (a) (b) (c)

The spacing of adjacent atoms in a NaCl crystal is 0.282 nm, and the masses of the atoms are 3.82*10-26 kg (Na) and 5.89*10-26 kg (CI). Use this information to calculate the density of NaCl. p= kg/m³

Determine the angles a, ß, and y that are listed in the cubic unit cell provided. Enter the angles in degrees. Note: You should be able to use basic facts about cube geometry and crystallographic convention to solve this, rather than elaborate direction cosine equations. [00 1] (0 0 1) [1O 1] [11 1) (1 1 1) a = i B = i