Answered: Sample Problem # 05 Determine the…

Sample Problem # 05 Determine the resulting moment about point A for the system of forces acting on the plate ABCD'as shown in the diagram. 15 cm 20 N D 45° 8cm 300 35 N A 80° 10.38 cm 45 N

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Determine the moment of the force system shown in Figure (4) about 1/ Point B 2/ Point C 3/Point D Fig.(4) 200 N/m 1.25 m 1.5 m 1.25 m 250 N.m 150 N 25 m 1.5 m 300 N/m
Example: Determine the resultant moment of the forces shown in (Figure 1) about point A? F₁ = 250 N 30° A -2 m- -3 m- Figure 1 B F₂ = 300 N 60° 4 m 10 3 F3 = 500 N
Consider the system shown in (Figure 1). Figure C 7 ft F = 80 lb 3 ft B 2 1.5 ft 63 Part A Determine the moment of the force F about the door hinge at A. Enter the x, y, and z components of the moment in pound-feet to three significant figures and separated by commas. (MA)z. (MA)y, (MA) z = Submit Provide Feedback Request Answer VE ΑΣΦ ↓↑ vec = ? lb. ft Next >
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I know that the first two values are correct but I don't know what I am missing for the moment created by force 3 I think I should use the x component of F3 with the y component but I dont know what kind of distance vector I should use for the moment about A for the x component of F3 if you could tell me what I'm missing I would be really greatful
The eyebolt shown in figure below is intended to hold several cables which exert the known forces shown. Calculate the resultant and its direction of these .forces G =4 kN 20° F = 3 kN 40° 30° 40° H = 5 kN K =2 kN R = 0.333 kN and 0 = 32 Degree R = 0.222 kN and 0 = 22 Degree R = 0.444 kN and 0 = 42 Degree
The force P = 620 lb and force Q 620 lb are applied at point A and B of the bell cranck shown, respectively. (a) compute the moment of the force P about O and (b) value of 60° 45° the force Q to make the moment at O equal to zero. 45° 100 mm 550 180 mm
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The moment of the force F=120-lb about the point O in Cartesian vector form is. F-120 lb 1ft 4 ft 2 ft Select one: a. Mo = 200j - 400k b. Mo = -200j+ 400k c. Mo = -200j- 400k O d. Mo = 200j+ 400k
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Q/ Find the resultant (R) and the direction (N) of the two forces shown in Figure below ? The angle (N) is measured between (R) and the x-axis. O 4 kN 50° 30° y 30° 6 kN Resultant = 6 KN & Direction = 60 O all of the above Resultant = 6.61 KN & Direction = 66.6 Resultant = 6.61 & Direction = 60