Based on Problem 4-9 from the textbook. The cable exerts a force P at the end of the crane boom. Determine the position of the boom so that force P creates a maximum moment about point O. What is this moment? p=4.8Kn x=12.9m y=7.6m 1m
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- HOME WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B,C (x, y, z) 2- Find FAR and FAC 3- Find |raR| and Iracl 4- Find FAR = F UAB and FAC = F UAC 5- Finally find R and a, B,Y 3m Fc= 500N FB= 500N 3m 5m 3m B 4m 2m 5mHelp Save & Exit Check Required information A rope connecting points A and B supports the force Fshown in the figure. Write expressions using Cartesian vector representation for the following. Take L= 8 ft and F= 12 lb. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. B 30° F T AB : the position vector from A to B. TAB of 17 Next > < Prev 6. 9. 41The L-shaped rod AOCD has an 80 kg mass hanging from it at B. The rod is leaning against a smooth wall at A. Point B is half way up OA. There is a journal bearing at C and a thrust bearing at D. They are properly aligned. A force F is pulling in the x-direction at B. Just as the rod comes off of the wall at A, what is the magnitude of the force F. 1 m B F 1m
- An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F1=200 lbf, F2=250 lbf, and F3=100 lbf with 0 = 30 degrees and p=24.1 degrees. If the eye bolt is in equilibrium, what is the x-component of the sum of other forces on the bolt (force from the nut and plate on the bolt) ? If you add up the three force vectors, the sum other force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The x-direction is positive to the right. For example, if you find the sum of forces 1, 2, and 3 are 100 Ibf to the right, then the other forces in the x-direction must be pointing to the left (-100 lbf) to put the eye bolt in equilibrium. Eye bolt 2steel 3 plate Nut t WonsherPS2-5 Three forces are acting on the problem. List all of the simplifications that can be used in the problem. What is the simplest problem? F₂ 45° RPlease help. Please make sure you clearly state how you got the numbers you got and why you are using them. Also please make sure you clearly put your formulas and label your units along the numbers that you are using. In the following frame ilustration, F1s 60 N and F2 is 9 N. What is the tension in the cable AB and the reaction force vector necessary to keep the system in static equilibrium? Give the X component reaction force at C( for an x axis going left to right). Also please solve for the rest of the 3 unknowns please. Thank you
- The 300kn sphere is supported by a pull p and a 200kn weight passing over a frictionless pulley. If a=30°. Computer the value of p and tangent.The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. ResponseProblem Statement Based on Problem 4-151 from the textbook. The pipe assembly is subjected to the action of a wrench at B and a couple at A. Simplify this system to a resultant wrench and specify the locaiton of the wrench along the axis of pipe CD, measured from point C. F = 42.8 N 0.6 m X Z C 0.8 m (60k) N 0.25 m {-401) N B 0.25 m - Fi 0.3 m 0.7 m V-60k) N A 0.3 m Fi 0.5 m D y
- Equilibrium of Concurrent Force System. The piston of a reciprocating engine exerts a force of 175 kN on the crosshead when the crank is 45° (angle B) past TDC. If the stroke of the piston is 800 mm and the length of the connecting rod is 1.80 m, find the guide force and the force in the connecting rod. Hint: 1=½ stroke; Angle o may be solved using Sine Law in AACO. K= Compressive Force in the connecting Rod E= Piston Effort 70 120 F, = Guide Force Fig. P-1 Fig. P-2 a Tools: EF cos0=0; F sin .=0. R = Ev)* + (E#): ; R 771 =- : tane = sin A sin B sin C3-In the scheme below, 4 objects are hanging from each of the rings and 5 ropes (blue) keep the entire scheme in balance. The known values are m1=30 kgm1=30 kgα=60ºα=60ºβ=30ºβ=30ºγ=70º a) Attach the force diagram on each of the rings with the graphical decomposition of the forces that are not exclusively on the Cartesian axes. b) Determine the tractions T1, T2, T3, T4 and T5. c) Determine the mass of weights 2, 3, 4 and 5. Tip: If you feel comfortable, use software to solve the systems of equations.The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal.